PHP stripping out specific text from string

Question

I think I'm going about this the wrong way, but here's what I'm doing.

I have a string passed to me from my PBX, which I'm attempting to grab only the phone number, and even the text inside the double quotes, if they exist.

<?php
  $string = '"John Smith" <sip:[email protected]:5060;user=phone>';
?>

I'm positive using a form of regex will be better to grab the number and name in separate variables, but since I'm not too good at regex yet, I'm resorting to explode()

I'm not doing too well with it, and it's getting messing with exploding the string at the @ sign, then at the :. This leaves the name.

How would I strip out the number after the <sip: before the @?

Answer 1

First thing you may want to do is to split (using regexp) into part before and after <sip:

^(.*?)\s*<sip\:(.+)>\s*$

\s* means to skip any white spaces if there are any.

Matching phone number is:\d+ or [0-9]{1,} or whichever combo you like.

Matching the contents of "" would be trivial if you can rely that they are always there: \s*"([^"]+)"\s* or little worse if they are just optional: \s*(?:"([^"]+)"\s*)?

So lets put it all together:

$regex = '~^\s*(?:"([^"]+)"\s*)?<sip:(\d+)@.+>\s*~i';
$matches = array();
if( preg_match($regex, $string, $matches)){
    list(, $name, $phone) = $matches;
}

Answer 2

Here's how to do it with regexp:

preg_match('/(?:"([^"]*)")?\s*<.*sip:(\d+\)/', $string, $match);
$name = $match[1];
$phone = $match[2];

Answer 3

if (preg_match('/^(?:\"([^\"]+)\" )?\<sip\:(\d+)\@/i', $string, $matches))
    list(, $name, $phone) = $matches;

Answer 4

<sip:([0-9]{1,})@

is the regex you need

preg_match('/".*?" <sip:([0-9]+)@/', $string, $matches); 
//matches[1] contains the name
//matches[2] contains the number

Answer 5

check this

<?php

  $string = '"John Smith" <sip:[email protected]:5060;user=phone>';

  $first = explode("<sip:", $string);

  $second =  explode("@", $first[1]);

  echo $second[0];
?>