foreach statement not returning all values within an Array?

Question

I have a very simple Array that contains a link, and the link title. When I print the Values, for some reason the "3rd" value is missing. I have double checked to make sure the 3rd value exists, and it does. I do not understand what is happening? Any suggestions would be great!!!

<?php

$resources = array(
    "$link" => "$link_name",
    "$link1" => "$link_name1",
    "$link2" => "$link_name2",
    "$link3" => "$link_name3",
    "$link4" => "$link_name4"
);

foreach ($resources as $resources_link => $resources_name) {
    echo "<a href=\"$resources_link\">$resources_name</a><br>";
}
?>

The out put looks like: (Missing the 3rd value) Link1 Link2 Link4 Link5

and why do you need to put your variables in the array in double quotes? — Jürgen Paul
– Jürgen Paul, Commented Apr 15, 2012 at 14:50
Are you sure you never passed that array by reference? That would corrupt the array, and you would need to reset() it before your foreach. — o0'.
– o0'., Commented Apr 15, 2012 at 14:56

Hüseyin Z. · Accepted Answer · 2012-04-15 14:54:44Z

2

I tried this code and works perfectly fine:

<?php

$link = "www.google.com";
$link_name = "Google";

$link1 = "www.google1.com";
$link_name1 = "Google1";

$link2 = "www.google2.com";
$link_name2 = "Google2";

$link3 = "www.google.com3";
$link_name3 = "Google3";

$link4 = "www.google.com4";
$link_name4 = "Google4";

$resources = array("$link"=>"$link_name","$link1"=>"$link_name1","$link2"=>"$link_name2","$link3"=>"$link_name3","$link4"=>"$link_name4");
foreach ($resources as $resources_link => $resources_name) {

echo "<a href=\"$resources_link\">$resources_name</a><br>";
}

answered Apr 15, 2012 at 14:54

Hüseyin Z.

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Comments

Satya · Accepted Answer · 2012-04-15 14:54:28Z

0

I tried your code modifying it a bit and can see all five links:

<?php

$resources = array(
"1"=>"A",
"2"=>"B",
"3"=>"C",
"4"=>"D",
"5"=>"E"
);

foreach ($resources as $resources_link => $resources_name) {

echo "<a href=\"$resources_link\">$resources_name</a><br>";
}

?>

answered Apr 15, 2012 at 14:54

Satya

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Comments

senderle · Accepted Answer · 2012-04-15 17:13:06Z

0

The variable $link is not define, if it is just a string, replace double quotes with single quotes. like:

<?php

$resources = array(
'$link'=>'$link_name','$link1'=>'$link_name1','$link2'=>'$link_name2','$link3'=>'$link_name3','$link4'=>'$link_name4');

foreach ($resources as $resources_link => $resources_name) {

echo "<a href=\'$resources_link\'>$resources_name</a><br>";
}
?>

edited Apr 15, 2012 at 17:13

senderle

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answered Apr 15, 2012 at 15:02

zckuang

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1 Comment

Rubble Over a year ago

Thank you for your help everyone. Something was happening with the variables coming from the database and the array was skipping vales/listing in desc order for some reason. I ended up having to use a few if statements, but was able to get the same results.

Muhammad Alvin · Accepted Answer · 2012-04-18 14:39:29Z

0

I suspect the value of $link, $link_name, $link1, $link_name1, ... have special HTML characters. Try to change your loop to:

foreach ($resources as $resources_link => $resources_name) {
    echo "<a href=\"" . htmlentities($resources_link) . "\">" . htmlentities($resources_name) . "</a><br>";
}

htmlentities() will sanitize your text, so it will not break any HTML tags.

answered Apr 18, 2012 at 14:39

Muhammad Alvin

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