Pass arguments from array in php to constructor [duplicate]

Question

This question already has an answer here:

Normally, if I want to pass arguments from $myarray to $somefunction I can do this in php using

call_user_func_array($somefunction, $myarray);

However this does not work when the function one wishes to call is the constructor for an object. For fairly obvious reasons it does not work to do:

$myobj = new call_user_func_array($classname, $myarray);

is there something fairly elegant that does work ?

Gordon · Accepted Answer · 2010-08-03 11:16:09Z

up vote 21 down vote accepted

You can use the Reflection API:

ReflectionClass::newInstanceArgs — Creates a new class instance from given arguments.

Example:

$reflector = new ReflectionClass('Foo');
$foo = $reflector->newInstanceArgs(array('foo', 'bar'));

answered Aug 3 '10 at 11:16

Gordon♦
129k17200291

w3d · Answer 2 · 2010-08-03 11:20:27Z

up vote 0 down vote

Or, you could just pass the array directly?

$myObj = new $classname($myArray);

And read the elements of the array inside the method as if they are parameters to that method (the constructor in this case).

answered Aug 3 '10 at 11:20

w3d
2,6511627

marked as duplicate by Gordon♦ Apr 1 at 14:03