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up vote 2 down vote favorite

How can I create a JSON with this format in Android: Since the API that I will be passing will parse JsonArray then the object. Or would it be okay if just to pass a json object? Since I will just have to insert 1 transaction per service call.

    {
        "student": [

            {
                "id": 1,
                "name": "John Doe",
                "year": "1st",
                "curriculum": "Arts",
                "birthday": 3/3/1995

            },
            {
                "id": 2,
                "name": "Michael West",
                "year": "2nd",
                "curriculum": "Economic",
                "birthday": 4/4/1994
            }
        ]
    }

What I know is only the JSONObject. Like this one.

     JSONObject obj = new JSONObject();
            try {
                obj.put("id", "3");
                obj.put("name", "NAME OF STUDENT");
                obj.put("year", "3rd");
                obj.put("curriculum", "Arts");
                obj.put("birthday", "5/5/1993");

            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

Any ideas. Thanks

share|improve this question
1  
what's the isseu? –  blackbelt Jul 23 at 12:21
1  
reference link –  chintan khetiya Jul 23 at 12:22
 
putting the JSONObject in a JSONArray to achieve the format posted.. –  sftdev Jul 23 at 12:22
 
Take a look at the JSONArray class developer.android.com/reference/org/json/JSONArray.html –  user634545 Jul 23 at 12:23

3 Answers

up vote 2 down vote accepted

Use the following code:

JSONObject student1 = new JSONObject();
try {
    student1.put("id", "3");
    student1.put("name", "NAME OF STUDENT");
    student1.put("year", "3rd");
    student1.put("curriculum", "Arts");
    student1.put("birthday", "5/5/1993");

} catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

JSONObject student2 = new JSONObject();
try {
    student2.put("id", "2");
    student2.put("name", "NAME OF STUDENT2");
    student2.put("year", "4rd");
    student2.put("curriculum", "scicence");
    student2.put("birthday", "5/5/1993");

} catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}


JSONArray jsonArray = new JSONArray();

jsonArray.put(student1);
jsonArray.put(student2);

JSONObject studentsObj = new JSONObject();
    studentsObj.put("Students", jsonArray);



String jsonStr = studentsObj.toString();

    System.out.println("jsonString: "+jsonStr);
share|improve this answer
up vote 2 down vote

You can create a a method and pass paramters to it and get the json as a response.

  private JSONObject jsonResult(String Name,int id, String curriculum) throws JSONException {
        JSONObject json = null;
        json = new JSONObject("{\"" + "Name" + "\":" + "\"" + Name+ "\""
            + "," + "\"" + "Id" + "\":" + id + "," + "\"" + "Curriculum"
            + "\":" + "\"" + curriculum+ "\"" + "}");
        return json;
      }

i hope this will help you.

share|improve this answer
up vote 0 down vote 
 JSONObject obj = new JSONObject();
            try {
                obj.put("id", "3");
                obj.put("name", "NAME OF STUDENT");
                obj.put("year", "3rd");
                obj.put("curriculum", "Arts");
                obj.put("birthday", "5/5/1993");

            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
             JSONArray js=new JSONArray(obj.toString());
             JSONObject obj2 = new JSONObject();
             obj2.put("student", js.toString());
share|improve this answer
 
i assume that 'obj' in 'JSONObject obj2 = new JSONObject(); obj.put("student", js.toString());' is 'obj2' ? –  sftdev Jul 23 at 12:47

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