std::binary_search
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Заголовочный файл <algorithm>
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template< class ForwardIt, class T > bool binary_search( ForwardIt first, ForwardIt last, const T& value ); |
(1) | |
template< class ForwardIt, class T, class Compare > bool binary_search( ForwardIt first, ForwardIt last, const T& value, Compare comp ); |
(2) | |
Проверяет, отсортированный диапазон
[first, last)
содержит элемент, равный value
. Первый вариант используется operator< для сравнения элементов, вторая версия использует данную функцию сравнения comp
.Original:
Checks if the sorted range
[first, last)
contains an element equal to value
. The first version uses operator< to compare the elements, the second version uses the given comparison function comp
.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Содержание |
[править] Параметры
first, last | - | диапазон элементов для изучения
Original: the range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
value | - | Значение для сравнения элементов
Original: value to compare the elements to The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have const &, but the function must not modify the objects passed to it. | |||||||||
Type requirements | |||||||||||
-ForwardIt must meet the requirements of ForwardIterator .
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[править] Возвращаемое значение
true, если элемент, равный
value
найдено, false иначе.Original:
true if an element equal to
value
is found, false otherwise.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[править] Сложность
Логарифмическая в расстоянии между
first
и last
Original:
Logarithmic in the distance between
first
and last
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[править] Возможная реализация
First version |
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template<class ForwardIt, class T> bool binary_search(ForwardIt first, ForwardIt last, const T& value) { first = std::lower_bound(first, last, value); return (first != last && !(value < *first)); } |
Second version |
template<class ForwardIt, class T, class Compare> bool binary_search(ForwardIt first, ForwardIt last, const T& value, Compare comp) { first = std::lower_bound(first, last, value); return (first != last && !(comp(value, *first)); } |
[править] Пример
#include <iostream> #include <algorithm> #include <vector> int main() { std::vector<int> haystack {1, 3, 4, 5, 9}; std::vector<int> needles {1, 2, 3}; for (auto needle : needles) { std::cout << "Searching for " << needle << '\n'; if (std::binary_search(haystack.begin(), haystack.end(), needle)) { std::cout << "Found " << needle << '\n'; } else { std::cout << "no dice!\n"; } } }
Вывод:
Searching for 1 Found 1 Searching for 2 no dice! Searching for 3 Found 3
[править] См. также
возвращает набор элементов для конкретного ключа Original: returns range of elements matching a specific key The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) |