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How do I find the exact area under the curve of the function $f(x)=4+3x-x^2$ on the interval $[-1,3]$ using integration. I'm super lost, and not quite sure how to start the problem.
This question already has an answer here: How do I find the exact area under the curve of the function $f(x)=4+3x-x^2$ on the interval $[-1,3]$ using integration. I'm super lost, and not quite sure how to start the problem. |
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Hints: $$\forall\,1\ne n\in\Bbb N\;,\;\;\int x^ndx=\frac{x^{n+1}}{n+1}+C$$ $$\int\limits_a^bx^ndx=\left.\frac1{n+1}x^{n+1}\right|_a^b=\frac{b^{n+1}-a^{n+1}}{n+1}$$ $$\int (f(x)+g(x))dx=\int f(x)dx+\int g(x)dx$$ | |||||||||||||||||||||
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$$\int_{-1}^{3}(4+3x+x^2)dx = \int_{-1}^{3}(4)dx + \int_{-1}^{3}(3x)dx+ \int_{-1}^{3}(x^2)dx$$ You should be able to solve those integrals rather easily. | |||||
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