split path and take last folder name in batch script

Question

I want to split the string (having a path) with \and take last folder name in a variable. Please help.

e.g
mypath=D:\FOLDER1\FOLDER2\FOLDER3\

I want FOLDER3 in a variable.

I tried with the command below which is working if the the last character is not \ :

for %f in (C:\FOLDER1\FOLDER2\FOLDER3) do set myfolder=%~nxf

It is not working if the last character is \

Also it is not working if variable is used like : for %f in (%mypath%) do set myfolder=%~nxf

user93353 · Accepted Answer · 2013-06-24 16:02:38Z

up vote 1 down vote accepted

@echo off

set MYDIR=C:\FOLDER1\FOLDER2\FOLDER3\
set MYDIR1=%MYDIR:~0,-1%

for %%f in (%MYDIR1%) do set myfolder=%%~nxf
echo %myfolder%

outputs

FOLDER3

answered Jun 24 at 16:02

user93353
5,7371929

Thank you very much. This code is working as per my requirement. – user2013 Jun 24 at 16:32

Endoro · Answer 2 · 2013-06-24 16:10:00Z

up vote 2 down vote

try:

for %f in (C:\FOLDER1\FOLDER2\FOLDER3\.) do set myfolder=%~nxf

works also:

for %f in (C:\FOLDER1\FOLDER2\FOLDER3.) do set myfolder=%~nxf

answered Jun 24 at 16:10

Endoro
20.5k3822

2 Answers