For specific question about eigenvectors of a matrix or a linear operator.

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1answer
47 views

Intuitive meaning of right and left eigenvector

I am trying to get an intuitive understanding of the meanings of right and left eigenvectors. I guess the best thing you can do is to provide examples of application. (Examples from the field of ...
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1answer
40 views

Characteristic polynomial divides minimal polynomial if and only if all eigenspaces are one-dimensional

Prove that characteristic polynomial of a complex matrix $A$ divides its minimal polynomial if and only if all eigenspaces of $A$ are one-dimensional. As far as I can see I the only possible case ...
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1answer
40 views

Solving Linear ODE using matrices

What I don't understand here is where or how the operator for this solution is formed. Shouldn't the values of the operator be A=(1,0,0,1)? (in the form a11, a12, a13, a14 respectively). Any help ...
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0answers
45 views

the spectrum and determinant of the Laplacian on $S^3$

I came across the following statement in a paper: On $S^3$, the eigenvalues of the vector Laplacian on divergenceless vector fields is $(\ell + 1)^2$ with degeneracy $2\ell(\ell+2)$ with $\ell ...
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5answers
55 views

Eigenvalues and eigenvectors - help

I was reading my lecture notes on using matrices to solve ODEs and came across this and am having trouble understanding it: (Please note that the two eigen values that are calculated are 2 and 0 ...
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3answers
51 views

Finding the jordan form of a funny looking matrix

I was working on this problem from a previous qual exam. Just when I thought I knew how to find the Jordan form of any matrix and then I find this....aaaargh :) Find the jordan form of the ...
3
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3answers
80 views

Why is $\det (A-\lambda I)=0$?

I'm not sure I understand the logic behind why $\det (A-\lambda I)=0$ for any non-trivial solution to $(A-\lambda I)x=0$.
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1answer
28 views

The generalized eigenvectors of linear operator $T$ span space $V$, why?

I'm studying about determinant and I have a problem understanding the following (Proposition 3.4): The problems I have are highlighted with red rectangles. If anyone can, could you clarify these ...
2
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1answer
23 views

Relation between eigenvectors of covariance matrix and right Singular vectors of SVD, Diagonal matrix

I have a $m \times n$ data matrix $X$, ($m$ instances and $n$ features) on which I calculate the Covariance matrix $C$ and perform eigenvalue decomposition. so $C=W \Sigma W'$ where $W$ are the ...
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0answers
14 views

recurrence relation basis vectors

I see that recurrence $x_n + c_1 x_{n-1} + \cdots = 0$, which may also be written as $x^n + c_1 x^{n-1} + \cdots = 0$ has a solution in the terms of eigenvalue powers, $$x_n = x_{01} \lambda_1^n + ...
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6answers
164 views

If $A\vec{v}=\lambda\vec{v}$, then does $A=\lambda$?

When my professor started teaching eigenvectors and eigenvalues the other day, the very first thing I noticed was the fact that $A\vec{v}=\lambda\vec{v}$ (assuming that the equation is satisfied under ...
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0answers
11 views

low rank decomposition of composite PSD matrix

The matrix $M=AVA^T - BCB^T +D$ is known to be positive semidefinite (PSD), where $V, C, D$ are each diagonal matrices with positive values, and $V, C$ has small size when compared to the size of $M$. ...
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0answers
40 views

Has this Principal Component Analysis (PCA) been done correctly?

I have a set of 3D data points, indicated by the blue color in the picture below. I then project them onto the x-y plane, i.e. setting z values of all the points to 0, shown by the yellow color ...
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0answers
24 views

Hermitian operator and its eigenbasis

Can anybody give me a simple proof for this theorem? the proofs that I have read are so confusing? For every Hermitian operator $W$, there exists a basis consisting of its orthonormal eigenvectors ...
0
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1answer
24 views

Eigenvalues of a second derivative

I have a function f(r) that describes a Gaussian random field. A second derivative can be formed $\nabla_i \nabla_j f(r)$. I am looking at a paper that claims that in finding the extremum, the ...

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