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Here is javascript code:

var jsonData = JSON.stringify(testObj);
            $.ajax({
              url: '../php/functions/spesific_field_set.php',
              type: 'post',
              data: {fieldObjArray: jsonData, tableName: fieldTableName}
              }).always(SpesificPropertiesSet);

and here is the php:

$updates = mysql_real_escape_string($_POST['fieldObjArray']);
$updates = json_decode($updates, true);
$tableName = mysql_real_escape_string($_POST['tableName']);

echo $updates;

What testObj is an array of object, how should I pass it to the php? and how should I access the data within this array of objects on php side?

thanks!!

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83% accept rate
var_dump($updates) after you json_decode() it to see what it looks like, and you'll have your answer. – Michael Berkowski yesterday
1  
By the way, unless you are inserting the whole JSON string directly into your database (which may be indicative of a poor design), don't call mysql_real_escape_string() on the input JSON from $_POST.. – Michael Berkowski yesterday
Learn about arrays: php.net/manual/en/language.types.array.php – Felix Kling yesterday
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1 Answer

up vote 0 down vote accepted

This is the PHP file. This should show you how you can access $updates that was sent through AJAX.

$updates = $_POST['fieldObjArray'];
$updates = json_decode($updates, true);
$tableName = $_POST['tableName'];
echo $updates; // this is an array so this would output 'Array'

foreach ($updates as $key => $value) {
    echo 'Key: '.$key.' Value: '.$value.'<br />'; // to access this, just use $updates['key']
}

// example
echo $updates['something'];
share|improve this answer
www.php.net/json_decode --> **assoc**: When TRUE, returned objects will be converted into associative arrays. This was initially set to true in the OP's code – rationalboss yesterday
indeed, sorry I missed that. Still though, it is going to be a 2D array, so the 1D loop will just output Array,Array,Array – Michael Berkowski yesterday
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