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I am returning an array of values using mysql_fetch_array.

In the while loop, i need to perform an if condition on the next element of the array.

E.g 

if next($row) == 'test'
{
...
}

The thing is 'next($row)' is returning me the index of the next element in the array. I would like to test for the next $row("name").

if next($row("name")) == 'test'
    {
    ...
    } //this code is incorrect

Is there a way of doing this in php?

Thanks a lot for your help :)

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Duplicate question of this: stackoverflow.com/questions/396519/… – Tom Oct 25 '11 at 10:09

2 Answers

up vote 2 down vote accepted

if the "next($row)" gives you the index of the next cell in the array then just use it to perform the test. $arr[next($row)] = the next cell value/obj/whatever you have there

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up vote 1 down vote 
foreach ($rows as $k => $row) {
    if (isset($rows[$k+1]) && $rows[$k+1] == 'test') //do something

    // Do normal stuff here
}
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