PHP variable inside a javascript function

This is just to clarify, but you seem to have a typo (d should be dd). Corrected:

<a class="code" href="javascript:void(0);"
   onclick="return (function () {
       if(window.dd && dd.elements) 
           dd.elements.name1.moveTo(<? echo $xpos; ?>, <? echo $ypos; ?>);
       return false; 
    })()"
>
    name1.moveTo(name1.x-20, name1.y+7);
</a>

Some issues:

• You don't need PHP variable interrpolation, $xpos by itself is fine
• onclick should have only one expression that returns false, so you'd ideally wrap it in a function elsewhere. Here I used an anonymous one

Also, onclick need not start with 'javascript:, since it already is implicitly so.

My guess would that xpos and ypos are not in scope at the time that part of the page is processed.

Scope refers to the enclosing braces. for example the following will not work

$xpos = 100;

function printx(){
  echo $xpos; // enclosing quotes not required
}

// call the function
printx();

Nothing will be printed

to fix it use the following

$xpos = 100;

function printx(){
  global $xpos;
  echo $xpos; // enclosing quotes not required
}

// call the function
printx();

this would then print 100