php check if array contains all array values from another array

Question

$all = array
(
    0 => 307,
    1 => 157,
    2 => 234,
    3 => 200,
    4 => 322,
    5 => 324
);
$search_this = array
(
    0 => 200,
    1 => 234
);

I would like to find out if $all contains all $search_this values and return true or false. any idea please?

jasonbar · Accepted Answer · 2012-03-11 14:21:05Z

up vote 16 down vote accepted

Look at array_intersect()

<?php
$containsSearch = count(array_intersect($search_this, $all)) == count($search_this);

answered Mar 11 '12 at 14:21

jasonbar
6,3961633

thanks, it works! :) – peter Mar 11 '12 at 14:36

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James Kyburz · Answer 2 · 2012-03-11 14:20:19Z

up vote 0 down vote

I think you're looking for the intersect function

array array_intersect ( array $array1 , array $array2 [, array $ ... ] )
array_intersect() returns an array containing all the values of array1 that are 
present in all the arguments. Note that keys are preserved.

http://www.php.net/manual/en/function.array-intersect.php

edited Mar 11 '12 at 14:20

answered Mar 11 '12 at 14:19

James Kyburz
3,253512

thanks, it works! :) – peter Mar 11 '12 at 14:37

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php check if array contains all array values from another array

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