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I am trying to create a figure with 6 sub-plots in python but I am having a problem. Here is a simplified version of my code:

import matplotlib.pyplot as plt
import numpy

g_width = 200
g_height = 200
data = numpy.zeros(g_width*g_height).reshape(g_height,g_width)

ax1 = plt.subplot(231)
im1 = ax1.imshow(data)
ax2 = plt.subplot(232)
im2 = ax2.imshow(data)
ax3 = plt.subplot(233)
im3 = ax3.imshow(data)
ax0 = plt.subplot(234)
im0 = ax0.imshow(data)
ax4 = plt.subplot(235)
im4 = ax4.imshow(data)
ax5 = plt.subplot(236)
ax5.plot([1,2], [1,2])
plt.show()

The above figure has 5 "imshow-based" sub-plots and one simple-data-based sub-plot. Can someone explain to me why the box of the last sub-plot does not have the same size with the other sub-plots? If I replace the last sub-plot with an "imshow-based" sub-plot the problem disappears. Why is this happening? How can I fix it?

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Do you mean that the actual plotting area is smaller? This might be due to the y-axis values. In that case, you can use subplots_adjust –  Dman2 Sep 18 '13 at 14:24
    
Does this answer: stackoverflow.com/questions/5083763/… help you? –  Roman Susi Sep 18 '13 at 14:34

1 Answer 1

up vote 2 down vote accepted

The aspect ratio is set to "equal" for the 5imshow()calls (check by callingax1.get_aspect()) while forax5it is set toautowhich gives you the non-square shape you observe. I'm guessingimshow()` defaults to equal while plot does not.

To fix this set all the axis aspect ratios manually e.g when creating the plot ax5 = plt.subplot(236, aspect="equal")

On a side node if your creating many axis like this you may find this useful:

fig, ax = plt.subplots(ncols=3, nrows=2, subplot_kw={'aspect':'equal'})

Then ax is a tuple (in this case ax = ((ax1, ax2, ax3), (ax4, ax5, ax6))) so to plot in the i, j plot just call

ax[i,j].plot(..)
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It worked! Thank you! –  AstrOne Sep 21 '13 at 6:30

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