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up vote 1 down vote favorite

I am facing one strange situation while working with PHP's in_array(). Below is my code and its output

<?php
$process = array("as12"=>"deleted","as13"=>1,"as14"=>1);
if(!in_array(0, $process))
    echo "success";
else
    echo "not success";

//It's outputting "not success";

var_dump(in_array(0, $process));
//Output : null

var_dump(in_array(0, $this->tProcessActions) === true);
///Output : true

If we look at the $process array, there is no 0 value in it. Still it's giving me true if I check if(in_array(0, $process))

Can anybody has idea about it?

share|improve this question
1  
0 == "deleted". –  cbuckley Jun 21 '13 at 10:06

7 Answers 7

up vote 3 down vote accepted

If you need strict checks, use the $strict option:

in_array(0, $process, true)

PHP's string ⟷ int comparison is well known to be complicated if you don't know the rules/expect the wrong thing.

share|improve this answer
    
+1 from me too. –  NullPointer Jun 21 '13 at 10:10
    
By putting true last parameter solved an issue. I seen it before long time and forgot to add when there is a mixed values in array like you said string-int –  NullPointer Jun 21 '13 at 10:11
up vote 3 down vote

Try like

if(!in_array('0', $process)) {

or you can use search(optional) like

if(array_search('0',$process)) {
share|improve this answer
    
+1 from me. Yes. You're right. But why I need to put 0 in Quotes? If I search for 1 without Quotes then it's giving correct result. –  NullPointer Jun 21 '13 at 10:07
2  
Because 0 == "deleted" using loose comparison. Note the third parameter to in_array, which forces strict comparison. Also have a look at the type comparison tables. –  cbuckley Jun 21 '13 at 10:07
up vote 1 down vote

I believe you should put 0 inside the quotes:

if(!in_array("0", $process))

share|improve this answer
up vote 0 down vote

I think because in_array maybe not strict type check. because if you check

 if (0 == "deleted") echo "xx";
share|improve this answer
up vote 0 down vote

Try this

if(!in_array('0', $process))
share|improve this answer
up vote 0 down vote

using the strict parameter gives what you want here:

$process = array("as12"=>"deleted","as13"=>1,"as14"=>1);
var_dump( in_array(0, $process, true ) );
// gives false

or use array_search and test if non-false;

var key = array_search( 0, array( 'foo' => 1, 'bar' => 0 ) );
// key is "bar"
share|improve this answer
up vote 0 down vote

You need use third parameter [$is_strict] of in_array function. 

in_array(0, $process, true)

The point is what any string after (int) conversion equal to 0. (int) "deleted" => 0. So in_array without strict mode is equal to "deleted" == 0 which true. When you use strict its equal to "deleted" === 0 which false.

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