PHP array_search

This might help build your function:

$intersection = array_intersect($needle, $haystack);

if ($intersection) // $haystack has at least one of $needle

if (count($intersection) == count($needle)) // $haystack has every needle

You can use array_intersect() : http://php.net/manual/en/function.array-intersect.php

if (empty(array_intersect($needle, $haystack)) {
   //nothing from needle exists in haystack
}

$needle = array('first', 'second');
$haystack = array('fifth','second','third', 'first');

// Returns key 1 in haystack


function array_needle_array_search($needle, $haystack)
{
        $results = array();
        foreach($needle as $n)
        {
                $p = array_search($n, $haystack);
                if($p)
                    $results[] = $p;
        }
        return ($results)?$results:false;
}

print_r(array_needle_array_search($needle, $haystack));

$needle = array('first', 'second');
$haystack = array('fifth','second','third', 'first');

if(in_array($needle, $haystack)) {
     echo "found";
}

From Javascript equivalent of PHP's in_array():

in_array function

a = array(array('p', 'h'), array('p', 'r'), 'o');
if (in_array(array('p', 'h'), $a)) {
    echo "'ph' was found\n";
}
if (in_array(array('f', 'i'), $a)) {
    echo "'fi' was found\n";
}
if (in_array('o', $a)) {
    echo "'o' was found\n";
}