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I want to parse this json using jquery and each with a loop. I have only seen json examples where it is wrapped in array with a title such as results. How do I parse json like below...?

$.each(json.results, function() {
    console.log(this['title']);
});

[{"title":"About Us","url_title":"about_us","entry_id":"155","channel_id":"2","author_id":"1","status":"open","entry_date":"1287508538","edit_date":"20101209122240","expiration_date":"0","about_body":"We are the greatest.","about_image":"","about_staff_title":"Joe","about_extended":"More about us.","color":"d12626"},{"title":"Contact Us","url_title":"contact_us","entry_id":"223","channel_id":"2","author_id":"1","status":"open","entry_date":"1291918929","edit_date":"20101209122310","expiration_date":"0","about_body":"Email us.","about_image":"","about_staff_title":"Bob","about_extended":"","color":"080480"}]
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What is your expected outcome? – zizozu Dec 18 '11 at 5:18
2  
Like this? jsfiddle.net/TuhHt – Jared Farrish Dec 18 '11 at 5:21
Thanks Jared that worked perfect! – digitalbart Dec 18 '11 at 5:25
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2 Answers

up vote 3 down vote accepted 
$.each(json, function() {     
    console.log(this.title);
});
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@digitalbart - This is essentially the same answer as my comment. – Jared Farrish Dec 18 '11 at 5:28
1  
@JaredFarrish Do you want to post an answer and I will accept it – digitalbart Dec 18 '11 at 5:30
@digitalbart - No, it's ok. We posted it at the same time. – Jared Farrish Dec 18 '11 at 5:31
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up vote 1 down vote

Shouldn't it just be $.each(json, function() ... ) ? Your JSON is an array, no wrapper, so just pass it directly to $.each().

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I am not sure what you by passing it directly to $.each()? Can you elaborate – digitalbart Dec 18 '11 at 5:27
What both @Sudhir and @Jared show - if your JSON is an array, and you load it into a variable called json, just pass json as the first argument to $.each, rather than passing json.results. – nrabinowitz Dec 18 '11 at 5:29
Thanks that makes sense I over thought it. – digitalbart Dec 18 '11 at 5:32
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