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up vote -1 down vote favorite

When I dump the variable it has a data:

var_dump($result);

object(stdClass)#2 (5) { ["user_id"]=> string(1) "1" ["username"]=> string(6) "user_name" ["email"]=> string(14) "[email protected]" ["password"]=> string(32) "password" ["test"]=> string(1) "1" }

But when I use foreach no value has return except if I just echo $data; but I want to be specific to the value I want to get.

foreach($result as $data){

echo $data->use_id;

echo $data->username;

}

Why there is no returned value?

share|improve this question
    
use echo $data->user_id not echo $data->use_id; –  Tamil Selvan Mar 3 '14 at 15:15

3 Answers 3

up vote 0 down vote

As you wrote: 

var_dump($result);

object(stdClass)#2 (5) { ["user_id"]=> string(1) "1" ["username"]=> string(6) "user_name" ["email"]=> string(14) "[email protected]" ["password"]=> string(32) "password" ["test"]=> string(1) "1" }

So the result is an object itself. so if you want specify and fetch exact variable, there's no need to iterate it!

share|improve this answer
    
Sorry, I don't know that yet. By the way thanks. :| –  Jopay Feb 18 '13 at 8:40
up vote 0 down vote

You don't need to iterate over the object. Just do this.

echo $result->user_id;
echo $result->username;

With the sample you provided you are treating each property in $result as an object and looking for user_id and user_name (which don't exist).

share|improve this answer
    
only it is actuall username,and not user_name. user_name is value. Look: ["username"]=> string(6) "user_name" –  Bojan Kovacevic Feb 18 '13 at 8:37
    
Thank you. Don't know that yet. :D –  Jopay Feb 18 '13 at 8:39
up vote 0 down vote

Try this : json_decode converts json string to array. Ref: http://php.net/manual/en/function.json-decode.php

$array  = json_decode($result, true);

echo "<pre>";
print_r($array);

You can use foreach to $array and echo the result.

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