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  • How to split string using batch script?

SET java_path="C:\Program Files\Java\jdk1.6.0_31"

above is my string, i want only "C:\Program Files" from java_path. how to get it?

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2 Answers

up vote 1 down vote accepted

You may split strings by character position:

ECHO %java_path:~1,16%

or by splitting at specific characters:

FOR /F "DELIMS=\ TOKENS=1,2" %i IN (%java_path%) DO ECHO %i\%j

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up vote 2 down vote

try this:

@ECHO OFF &SETLOCAL
SET "java_path=C:\Program Files\Java\jdk1.6.0_31"
SET "this=%java_path:~3%"
SET "this=%this:*\=%"
CALL SET "this=%%java_path:%this%=%%"
SET "this=%this:~0,-1%"
ECHO %this%
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