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I have an rss in xml form with who contain (well formatted)

$xml = simplexml_load_file("/rss.xml");
echo $xml->item[0]->guid;

This code give me nothing. If I var_dump the $xml, I get 40 array.

Can someone guess why?

edit:

Well... is a NSFW commision so care.. RSS file -> http://www.xvideos.com/rss/rss.xml (view-source:http://www.xvideos.com/rss/rss.xml for chrome)

var_dump:

object(SimpleXMLElement)#1 (2) {
  ["@attributes"]=>
  array(1) {
    ["version"]=>
    string(3) "2.0"
  }
  ["channel"]=>
  object(SimpleXMLElement)#2 (6) {
    ["title"]=>
    string(11) "Xvideos.com"
    ["link"]=>
    string(23) "http://www.xvideos.com/"
    ["description"]=>
    string(43) "Xvideos, free hosting for free porn videos."
    ["lastBuildDate"]=>
    string(31) "Mon, 18 Nov 2013 05:03:00 +0100"
    ["ttl"]=>
    string(2) "20"
    ["item"]=>
    array(40) {
      [0]=>
      object(SimpleXMLElement)#3 (5) {
        ["title"]=>
        string(23) "..."
        ["description"]=>
        string(766) ".. "
        ["link"]=>
        string(59) "http://www.xvideos.com/..."
        ["guid"]=>
        string(12) "video5748963"
        ["pubDate"]=>
        object(SimpleXMLElement)#43 (0) {
        }
      }
      [1]=>
      object(SimpleXMLElement)#4 (5) {
        ["title"]=>
        string(48) "...s"
        ["description"]=>
        string(789) "..."
        ["link"]=>
        string(84) "http://www.xvideos.com/,,,"
        ["guid"]=>
        string(12) "video4863479"
        ["pubDate"]=>
        object(SimpleXMLElement)#43 (0) {
        }
      }
 ....
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4  
show your dump. And your XML –  Cfreak Nov 18 at 16:28
 
uh that doesn't sound right :s –  thelolcat Nov 18 at 16:30
 
edited with infos, mostly NSFW so care. –  ItalianOne Nov 18 at 16:35
1  
you should remove the porn links, is it an ad or a real question ? you are accessing the xml->item but items is in xml->channel->item, maybe the issue is here –  Koren Nov 18 at 16:41
 
As you can see in your var_dump, your item is not a direct child of $xml. echo $xml->channel->item[0]->guid;. –  Rocket Hazmat Nov 18 at 16:42
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2 Answers

up vote 2 down vote accepted

It should be like

$xml->channel->item[1]->guid

that gets you the guid.

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up vote 0 down vote

This is the structure of a typical RSS file:

<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:atom="http://www.w3.org/2005/Atom">
    <channel>
        ...
        <item>...</item>
        <item>...</item>
        ...
    </channel>
</rss>

In your call, you have to omit the top level node (<rss> in this case) but not second level nodes:

echo $xml->item[0]->guid; // <channel>?
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