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up vote 6 down vote favorite

I need to encode a javascript function into a JSON object in PHP.

This:

$function = "function(){}";
$message = "Hello";

$json = array(   
      'message' => $message,
      'func' => $function
);
echo json_encode($json);

outputs:

{"message":"Hello","func":"function(){}"}

What I want is:

{"message":"Hello","func":function(){}}

Can I do this with json_encode?

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4 Answers

up vote 8 down vote accepted

As Jani said, this is not possible directly with JSON, but this might help you : http://solutoire.com/2008/06/12/sending-javascript-functions-over-json/

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1  
That works, although it's not really JSON anymore. –  Matthew Crumley Nov 17 '09 at 3:12
 
It is a valid JavaScript/Jscript/ECMAScript object, right? –  David Murdoch Nov 17 '09 at 18:26
 
Yes, as long as you parse it with eval instead of using a strict JSON parser. –  Matthew Crumley Nov 18 '09 at 2:53
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up vote 7 down vote

No. JSON spec does not support functions. You can write your own code to output it in a JSON-like format and it should work fine though.

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up vote 3 down vote

If don't want to write your own JSON encoder you can resort to Zend_Json, the JSON encoder for the Zend Framework. It includes the capability to cope with JSON expressions.

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1  
Good Lord, this is awesome. –  Stephen J. Fuhry Dec 3 '09 at 19:15
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up vote -1 down vote

you cannot do it with json_encode but u can do it afterwards in javascript 

json = {"message":"Hello","func":"function(){ alert(this.message) }"}

javascript:

eval('json.func = '+json.func);

call:

json.func();
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