PHP array to JavaScript array via Ajax request

Question

I want the result of this Ajax request to fill the JavaScript hintArray. That is, I want hintArray to contain the same values as $row. Can this be done in a simple way? How should the php file output be made? Is hintArray = JSON.parse(this); correct?

Many thanks

JavaScript

var hintArray = new Array();
postAjaxRequestFunktion(minFunktion, 'getHint.php', 'id =1')
function minFunktion()
{
  hintArray = JSON.parse(this); 

}

function postAjaxRequestFunktion(minFunk,minUrl, mittArg)
{
   var contenttype = 'application/x-www-form-urlencoded'
   var minRequest        = new skapaAjaxObjekt(minFunk)
   if (!minRequest) return false
   minRequest.open('POST', minUrl, true)
   minRequest.setRequestHeader('Content-type',   contenttype)
   minRequest.setRequestHeader('Content-length', mittArg.length)
   minRequest.setRequestHeader('Connection',     'close')
   minRequest.send(mittArg)
   return true
}

function skapaAjaxObjekt(minFunk)
{
   try       { var   minRequest = new XMLHttpRequest()                   }
   catch(e1) { try { minRequest = new ActiveXObject("Msxml2.XMLHTTP")    }
   catch(e2) { try { minRequest = new ActiveXObject("Microsoft.XMLHTTP") }
   catch(e3) { minRequest = false }}}
   if (minRequest) minRequest.onreadystatechange = function()
   {
      if (this.readyState == 4 && this.status == 200 &&
          this.responseText != null)
            minFunk.call(this.responseText)
   }

   return minRequest
}       

getHint.php

$result = mysql_query("SELECT hint01,hint02 FROM main WHERE id = '00000001'");
if (!$result) {
    echo 'Could not run query: ' . mysql_error();
    exit;
}
$row = mysql_fetch_row($result);

Answer 1

you should encode your php array with

json_encode($your_array);

and decode it in javascript with eval

your_js_array = eval('(' + yourJSONtext + ')');