Tell me more ×
Stack Overflow is a question and answer site for professional and enthusiast programmers. It's 100% free, no registration required.
up vote 0 down vote favorite

this is what i have so far, i need to convert this string array into just an array of integers, the string array looks something like this

wholef[0] = "2 3 4";
wholef[1] = "1 3 4";
wholef[2] = "5 3 5";
wholef[3] = "4 5 6";
wholef[4] = "3 10 2";

these values come from a text file that i read from but now i need to convert this into one big array of integers, im trying to use the split method but im not sure if it will work on this kind of setup. if anyone can give me a better way it would be nice but i just need to convert this into an array of integers, thats really all i need.

for(int k = 0; k < fline; k++)
    {
        String[] items = wholef[k].replaceAll(" ", "").split(",");

        int[] parsed = new int[wholef[k].length];

        for (int i = 0; i < wholef[k].length; i++)
        {
            try 
            {
                parsed[i] = Integer.parseInt(wholef[i]);
            } catch (NumberFormatException nfe) {};
        }
    }

This is the new code im using now, its very close cause i only get one error

int q = 0;
        for (String crtLine : wholef) 
        {
            int[] parsed = new int[wholef.length];

            String[] items = crtLine.split(" ");
            for (String crtItem: items) 
            {
                parsed[q++] = Integer.parse(crtItem);
            }
        }

the error is this java:97: error: cannot find symbol parsed[q++} = Integer.parse(crtItem); ^ symbol: method parse(String) location: class Integer 1 error

share|improve this question
What are you doing with the brackets? I don't see any in your Strings? – Boris the Spider Mar 7 at 21:18
honestly i have no idea why that was in there but it has been fixed – user1721540 Mar 7 at 21:22
parsed[q++] = Integer.parse(crtItem) should be parsed[q++] = Integer.parseInt(crtItem) – nattyddubbs Mar 7 at 21:36

2 Answers

up vote 1 down vote accepted

This take your string array and dumps it into intwholef[n..total]; If you want it into a 2D array or an object array you have to do some additional. Then you can do an array of objects, and have each set of values as an attribute. 

 String[] parts = wholef[0].split(" ");
 int[] intwholef= new int[parts.length];

 for(int n = 0; n < parts.length; n++) {
    intwholef[n] = Integer.parseInt(parts[n]);
  }
share|improve this answer
got this to work nicely, my only question is, when i have the variables in the new array im unable to use them outside of the for loop, any way to fix this? – user1721540 Mar 7 at 21:51
up vote 3 down vote

Try this:

int i = 0;
for (String crtLine : wholef) {
     String[] items = crtLine.split(" ");
     for (String crtItem: items) {
          parsed[i++] = Integer.parseInt(crtItem);
     }
}
share|improve this answer
Make sure you reset i every iteration of wholef and that parsed gets set to correct size. – user1181445 Mar 7 at 21:23
That would break it - writing the same 3 elements into the array. As size unknown I would suggest using a List then calling toArray(). – Boris the Spider Mar 7 at 21:24
If it is known that each .split() will result in exactly 3 strings, parsed array can be safely initialized like this: int[] parsed = new int[3*wholef.length], if not, @bmorris591 is right, it will be better to have a List – niculare Mar 7 at 21:29
This is good, i narrowed it down to 1 error but im not sure on how to fix it. i will add to details underneath all of my post – user1721540 Mar 7 at 21:29
Integer.parse isn't a method. – nattyddubbs Mar 7 at 21:37
show 1 more comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.