Tell me more ×
Stack Overflow is a question and answer site for professional and enthusiast programmers. It's 100% free, no registration required.
up vote 0 down vote favorite

I got the following class and I want to know if it is possible to use a variable array name.

class Ajax{
    private $method;

    public function __construct(){
        $this->method = '$_' . $_SERVER['REQUEST_METHOD'];
    }
}

So basically the $method variable should either contain the POST or GET method, next question is also if it is smart to use a reference here?

My first thought was:

$this->method = '$_' . $_SERVER['REQUEST_METHOD'];
$this->metod =& $$this->method;

But that is not working.

Thanks for reading and help, much appreciation.

share|improve this question
What do you want? Do you means pass the $_POST or $_GET to $this->method? – xdazz Feb 13 '12 at 14:16
@xdazz check the comment I posted on the first answer :) Thanks for comment anyway. – randomKek Feb 13 '12 at 14:17
$this->method will contain $_POST or $_GET but it is not same as Global varible even if you are refernce then it wil reference to string'$_POST' or $_GET – Poonam Feb 13 '12 at 14:18
@Poonam also check the comment I posted on the first answer for my idea of this class. – randomKek Feb 13 '12 at 14:19
When do you call the Ajax class? Either you catch every request in an index.php file and then decide what do or you can save the request method and pass the type when initiating the ajax class: $ajax = new Ajax($type); – busypeoples Feb 13 '12 at 14:29
show 1 more comment

3 Answers

up vote 1 down vote accepted

Why not just do 

If ($_SERVER['REQUEST_METHOD'] === 'GET') {
    $this->method = $_GET;
} else if ($_SERVER['REQUEST_METHOD'] === 'POST') {
    $this->method = $_POST;
}

If you want to directly work, then

$this->method = ${'_'.$_SERVER['REQUEST_METHOD']};

OR you can just use the $_REQUEST (although it is not very good to use it)

$this->method = $_REQUEST;
share|improve this answer
Yeah I figured that one out, just wanted to know if it was possible if I could use it without the IF statement, gonna use this anyway. Do you know if it a good idea to use $this->method =& $_GET, so a reference or not? – randomKek Feb 13 '12 at 14:25
The reference is not necessary. – xdazz Feb 13 '12 at 14:30
I know it is not necessary, but would it be smart to use a reference else we got the data twice in memory right? – randomKek Feb 13 '12 at 14:37
no,won't be twice, php use copy on write, don't worry about that. – xdazz Feb 13 '12 at 15:40
up vote 1 down vote

You'd want something like

    $this->method = $$_SERVER['REQUEST_METHOD'];

this being a "variable variable" (note the double $$). However, please don't do this. variable variables make for difficult-/impossible-to-debug code.

share|improve this answer
My idea is to create a ajax controller, with 3 variables, 1. json, 2. errors, 3. method. Once an action of the controller is called, we use whitelist validation, using the method variable that points to the request array, then if the validation pass, we set the json variable, finally the destructor of the class does echo json_encode($this->json). So than we have a nice solid ajax class using whitelist validation in a simple way :) – randomKek Feb 13 '12 at 14:16
Ain't working it isn't pointing to the POST or GET array. When I print out $this->method it will return NULL while the POST definatly contained data. – randomKek Feb 13 '12 at 14:21
That's why I said "something like". This'll evaluate to "POST", not "_POST", so you're not really assigning the _post data array. – Marc B Feb 13 '12 at 14:32
up vote 1 down vote

try to get it like this:

$this->method = ${'_' . $_SERVER['REQUEST_METHOD']};

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.