why output limit exceeded in this code

Question

class Solution {
public:
    vector<vector<int> > threeSum(vector<int> &num) {
        vector<vector<int>>v;
        int i,j,t,k,temp;
        sort(num.begin(),num.end());
        vector<int>b;
        int n=num.size();
        for(i=0;i<n;)
        {
            t=-1*num[i];
            j=i+1;
            k=n-1;
            while(k>j)
            {
                int temp=num[k]+num[j];
                if(temp==t)
                {
                    b.push_back(num[i]);
                    b.push_back(num[j]);
                    b.push_back(num[k]);
                    v.push_back(b);
                    j++;
                    k--;
                    b.clear();
                }
                else if(temp<t)
                {
                    j++;
                }
                else
                k--;
            }
            t=num[i];
            while(t==num[i])
            i++;
        }
        return v;
    }
};

Comments

Could you please update your post with the explanation of your algorithm and add comment in your code? Thanks.

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Thanks for your reply. My problem is solved now. Actually,I forget to skip same numbers that caused output limit exceeded. My algorithm is to select one number. and use the concept of 2 sum problem.

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leetcode must update recently, because it can be accepted without skip the same number before.

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Yes, the judge is stricter now and some sub-optimal solutions were prevented from passing the judge.