current community

your communities

more stack exchange communities

Stack Exchange
tour help
careers 2.0
Take the 2-minute tour ×
Stack Overflow is a question and answer site for professional and enthusiast programmers. It's 100% free, no registration required.
up vote 9 down vote favorite
3

I have an JavaScript object like this:

id="1";
name = "serdar";

and I have an Array which contains many objects of above. How can I remove an object from that array such as like that:

obj[1].remove();
share|improve this question

7 Answers 7

up vote 19 down vote accepted

Well splice works:

var arr = [{id:1,name:'serdar'}];
arr.splice(0,1);
// []

Do NOT use the delete 'delete' operator on Arrays.

But maybe you want something like this?

var removeByAttr = function(arr, attr, value){
    var i = arr.length;
    while(i--){
       if(arr[i] && arr[i].hasOwnProperty(attr) && (arguments.length > 2 && arr[i][attr] === value )){
           arr.splice(i,1);
       }
    }
    return arr;
}

var arr = [{id:1,name:'serdar'},{id:2,name:'alfalfa'},{id:3,name:'joe'}];
removeByAttr(arr, 'id', 1);
// [{id:2,name:'alfalfa'},{id:3,name:'joe'}]

removeByAttr(arr, 'name', 'joe');
// [{id:2,name:'alfalfa'}]

Just an example.

share|improve this answer
up vote 11 down vote

You can use either the splice() method or the delete operator.

The main difference is that when you delete an array element using the delete operator, the length of the array is not affected, even if you delete the last element of the array. On the other hand, the splice() method shifts all the elements such that no holes remain in the place of the deleted element.

Example using the delete operator:

var trees = ["redwood", "bay", "cedar", "oak", "maple"];  
delete trees[3];  
if (3 in trees) {  
   // this does not get executed  
}
console.log(trees.length);  //  5
console.log(trees);         //  ["redwood", "bay", "cedar", undefined, "maple"]

Example using the splice() method:

var trees = ["redwood", "bay", "cedar", "oak", "maple"];  
trees.splice(3, 1);
console.log(trees.length);  //  4
console.log(trees);         //  ["redwood", "bay", "cedar", "maple"]
share|improve this answer
up vote 0 down vote

Use the splice method.

(At least I assume that is the answer, you say you have an object, but the code you give just creates two variables, and there is no sign of how the Array is created)

share|improve this answer
up vote 0 down vote

Use delete-keyword.

delete obj[1];

EDIT: see: http://stackoverflow.com/questions/500606/javascript-array-delete-elements delete will undefine the offset but not completly remove the entry. Splice would be correct like David said.

share|improve this answer
    
Regarding "delete will undefine the offset but not completely remove" -- this is not entirely correct, as delete will totally remove the element as shown in the if (3 in trees) test in my answer. The only thing is that it does not shift the other elements to fill up the hole, so the length is not affected. Therefore, if you display the array, you'll get undefined where there is the hole.... –  Daniel Vassallo Aug 3 '10 at 11:55
    
... However, using delete is not the same as setting an element to undefined. This is also explained here: developer.mozilla.org/en/Core_JavaScript_1.5_Reference/… –  Daniel Vassallo Aug 3 '10 at 11:55
    
@daniel: I expressed myself incorrect but I meant the same. :-) –  Stefan Hoth Aug 3 '10 at 12:04
up vote 0 down vote 
delete obj[1];

Note that this will not change array indices. Any array members you delete will remain as "slots" that contain undefined.

share|improve this answer
up vote 0 down vote

If it's the last item in the array, you can do obj.pop()

share|improve this answer
up vote 0 down vote

If you know the index that the object has within the array then you can use splice(), as others have mentioned, ie:

var removedObject = myArray.splice(index,1);
removedObject = null;

If you don't know the index then you need to search the array for it, ie:

for (var n = 0 ; n < myArray.length ; n++) {
    if (myArray[n].name == 'serdar') {
      var removedObject = myArray.splice(n,1);
      removedObject = null;
      break;
    }
}

Marcelo

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.