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In my class, I always write the date using mathematical formulas, or cool little equations. I want to show my students that even the most mundane seeming number often has fascinating features, and its own beauty - that's the reason I got into mathematics, and I want to pass it down.

For example, for 30, I wrote $\frac{6!}{4!}$.

Now, 2014 has kind of stumped me. The best I could come up with was this, using factorials:

$$(2!(2!+2!(4!))+3!)(4!-3!+1!)$$

But, this seems too longwinded. I'm looking for something short and snappy.

What do you think the best (nerdiest?) way to write 2014 is?

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"Best" - shortest, more concise. "Nerdiest" - using mathematical functions in interesting ways. –  James Williams yesterday
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You could play around with different bases: it's $a3c_{14}$, or $7de_{16}$. Another nice one is $bbc_{13}$. –  user88595 yesterday
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Or $2kg_{27}$ . –  user88595 yesterday
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$13^3-13^2-13^1-13^0$ (Courtesy of the OEIS) –  Jack M yesterday
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@JackM Go ahead and make that an answer! –  James Williams yesterday
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12 Answers

Looking $2014$ up in the OEIS turns up:

$$2014=13^3-13^2-13^1-13^0$$

In general, looking a number up in the OEIS is probably a reasonable way to turn up pleasing identities.

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Give them the following :

$$(-2+0+1+4)^{(2+0+1+4)}-(2+0+1+4)^{(-2+0+1+4)}+(2+0-1+4)^{(-2+0+1+4)}+(2+0-1+4)\cdot(-2+0+1+4)^2=?$$

and tell them to compute the result.

All you can see is only 2014 with some sign changed and of course the result is simply
$$3^7-7^3+5^3+5\cdot3^2=2014$$
It will look better on a board.

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1  
I like this one; With all due respect, but many of the other answers don't look more interesting to me than 2⋅10³+0⋅10²+1⋅10¹+4⋅10⁰. –  Mr Lister 17 hours ago
 
@MrLister thank you very much for the comment –  Konstantinos Gaitanas 14 hours ago
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With all due credit to this base 13 answer on codegolf.SE:

$$2014=BBC_{13}$$


Or just playing with my calculator, I like the look of

$$2014=5^5-1111$$

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I hope you will enjoy the following spoof :

$\qquad\quad$ I remember once going to see him for the Holidays, and remarked that the number of the upcoming year seemed to me rather a dull one, and that I hoped it was not an unfavorable omen. "No," he replied, "it is a very interesting number; it is the smallest number which can be expressed as the product of three distinct primes, which are congruent modulo $17$." $:)$

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What it lacks in brevity, it makes up for in nerdiness:

SSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS$0$

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4  
I like it ;) although I have a feeling that writing this out on a board could be rather monotonous –  James Williams yesterday
 
How is this $2014$? –  K. Rmth yesterday
 
@K.Rmth well, it appears to be 2014 S's and 1 zero. Not sure what the 0 is for (or why S was chosen) –  Tyler yesterday
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@K.Rmth $S$ is the successor function. So, for example, $S(4) = 5$. In general, $S(x) = x + 1$. –  Gamma Function yesterday
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Peano arithmetic has one constant symbol, 0, and one unary function symbol, $S$. Every natural number is either $0$ (in which case it is not the successor of anything) or the successor of some (unique) other natural number. Every natural number can thus be written as a finite number of applications of the successor function to the constant zero. Thus the natural numbers are defined recursively, which makes this essentially the minimal structure needed to enable inductive type proofs. (I'm simplifying slightly - some formulations of Peano Arithmetic permit nonstandard natural numbers.) –  Unwisdom yesterday
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Here are some cryptic ones: From the Gaussian integral we have $$2014 = \frac{4028}{\sqrt{\pi}}\int_{0}^{\infty}e^{-x^2}dx$$ and from the Basel Problem we have: $$2014 = \frac{12084}{\pi^2}\sum_{i=1}^{\infty}{\frac{1}{i^2}}$$ Here are some that (arguably) has deep meanings and roots: $$ 2014 = 2\cdot19\cdot53$$ $$2014 = 2^{11} - 34$$ For some trigonometry we have: $$2014 = \frac{4}{\cos^3{\frac{\pi}{9}}\cdot\cos^3{\frac{2\pi}{9}}\cdot\cos^3{\frac{4\pi}{9}}} - 34$$ It depends on perception, really. There are probably arguably infinitely many ways to write $2014$ in a "short, snappy, cool, and nerdy way".

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You definitely have the right idea here! I am intrigued as to how you worked out the first two in such a short time –  James Williams yesterday
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@JamesWilliams Well, you have 2*2014=4028 and 6*2014=12084, where the 2 and the 6 belonged to the (rather well known) cases where the 2014 is removed from both sides, and rearranged so the sum/integral are on their own side. –  FireGarden yesterday
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How about

$$3\cdot6!-5!-4!-2!$$

or, if you like

$$(6!-5!)+(6!-4!)+(6!-2!)$$

Alternatively:

$$6!2!+4!4!-2!0!$$

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(Self answering question) Find the integral part of the unique real root of the equation $$\log_2 x+\log_{20}x+\log_{201}x+\log_{2014}x -2-0-14+\frac{1}{20+\frac{1}{14}} = 0$$

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1  
Using "2014" in the expression itself is surely cheating. –  David Richerby yesterday
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Maybe do:

$$2014 = \sum_{k=0}^{11}\binom{11}{k}-34$$

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aka 2^11 - 34, since 2^11 = 2048 –  smci 10 hours ago
 
I like my way better :-) –  Patrick 6 hours ago
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$$ 2014 = 2^{2\times2^2 \times (2\times2^2-2)}-2\times (2\times2)^2-2 $$

Equations like this can be made for any number, not just 2014.

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Binary: 11111011110 Hexadecimal: 7DE

Image the students perplexing expression when they see: 1101/11/111111011110 or C/3/7DE Tell them to write this date in this form on there notes. Guaranteed they will show it to their friends or family.

Wow I can't believe I haven't thought of doing this with my students. As a rookie high school math teacher I am always looking for new 'hooks' with my students. Great idea and thank you!

Lesson planning using stack exchange? Who knew..

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If you're looking for "fascinating features" and you found only " too longwinded" formulae then you have for free the fascinating feature that 2014 is the first number for which you were not able to find a formula that is not "too longwinded"

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