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2

I have a trouble finding a way how to parse JSONArray. It looks like this:

[{"name":"name1","url":"url1"},{"name":"name2","url":"url2"},...]

I know how to parse it if the JSON was written differently (In other words, if I had json object returned instead of an array of objects). But it's all I have and have to go with it.

*EDIT: It is a valid json. I made an iPhone app using this json, now I need to do it for Android and cannot figure it out. There are a lot of examples out there, but they are all JSONObject related. I need something for JSONArray.

Can somebody please give me some hint, or a tutorial or an example?

Much appreciated !

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1  
Try this to see if your json is valid json.parser.online.fr –  Yume117 Sep 24 '13 at 9:02
 
are you using any library for parsing json? Use gson library for json parsing.Much Helpfull. –  nilkash Sep 24 '13 at 9:03
 
It is valid. I parsed it in an app i did for an iPhone And it's working. I just dont know how to do it in Android –  Stebra Sep 24 '13 at 9:03
1  
@nikash, yeah i noticed i could use gson. only problem is, all examples i found are for parsing a JSONObject not JSONArray –  Stebra Sep 24 '13 at 9:04
 
Post your code that you have tried so far.It will be helpful to give a precise answer accordingly. –  Spring Breaker Sep 24 '13 at 9:09
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6 Answers

up vote 3 down vote accepted

I'll just give a little Jackson example:

First create a data holder which has the fields from JSON string

// imports
// ...
@JsonIgnoreProperties(ignoreUnknown = true)
public class MyDataHolder {
    @JsonProperty("name")
    public String mName;

    @JsonProperty("url")
    public String mUrl;
}

And parse list of MyDataHolders

String jsonString = // your json
ObjectMapper mapper = new ObjectMapper();
List<MyDataHolder> list = mapper.readValue(jsonString, 
    new TypeReference<ArrayList<MyDataHolder>>() {});

Using list items

String firstName = list.get(0).mName;
String secondName = list.get(1).mName;
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Can you give me an example how would i get JSON as a string from url i have, please ? –  Stebra Sep 24 '13 at 10:37
1  
Weeell here's something that I made up: pastebin.com/w4thyPVK –  vilpe89 Sep 24 '13 at 11:24
1  
The DefaultHttpClients execute-method is a blocking call so it has to be done in a background task, just to make clear why it is in separate class. –  vilpe89 Sep 24 '13 at 11:39
 
Im being given an error about the constructor of HttpGetTask. "The constructor HttpGetTask(OnHttpGetCompletedListener) refers to the missing type OnHttpGetCompletedListener" –  Stebra Sep 24 '13 at 12:41
1  
have you imported OnHttpGetCompletedListener? Like this import your_package_name_here.HttpGetTask.OnHttpGetCompletedListener; –  vilpe89 Sep 24 '13 at 12:45
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up vote 3 down vote

use the following snippet to parse the JsonArray. 

  for (int i = 0; i < jsonarray.length(); i++) {

                JSONObject jsonobject = jsonarray.getJSONObject(i);
                String name=jsonobject .getString("name");
                String Url=jsonobject .getString("url");

           }

Hope it helps.

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up vote 3 down vote

Create a class to hold the objects.

public class Person{
   private String name;
   private String url;
   //Get & Set methods for each field
}

Then deserialize as follows:

Gson gson = new Gson();
Person[] person = gson.fromJson(input, Person[].class); //input is your String

Reference Article: http://blog.patrickbaumann.com/2011/11/gson-array-deserialization/

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I asume this "input" would be URL to that json? or is it something else? –  Stebra Sep 24 '13 at 9:09
 
@Stebra, Exactly, I included that as a comment in the code. –  Kevin Bowersox Sep 24 '13 at 9:09
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up vote 2 down vote

@Stebra See this example. This may help you. 

public class CustomerInfo 
{   
    @SerializedName("customerid")
    public String customerid;
    @SerializedName("picture")
    public String picture;

    @SerializedName("location")
    public String location;

    public CustomerInfo()
    {}
}

And when you get the result; parse like this

List<CustomerInfo> customers = null;
customers = (List<CustomerInfo>)gson.fromJson(result, new TypeToken<List<CustomerInfo>>() {}.getType());
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1  
Result variable is your JSONArray String –  nilkash Sep 24 '13 at 9:10
 
Would result variable be the url i need to fetch json from or already fetched json ? –  Stebra Sep 24 '13 at 9:22
1  
result string is already fetched JSONArray string –  nilkash Sep 24 '13 at 9:25
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up vote 2 down vote

In this example there are several objects inside one json array. That is,

This is the json array: [{"name":"name1","url":"url1"},{"name":"name2","url":"url2"},...]

This is one object: {"name":"name1","url":"url1"}

Assuming that you have got the result to a String variable called jSonResultString:

JSONArray arr = new JSONArray(jSonResultString);

  //loop through each object
  for (int i=0; i<arr.length(); i++){

  JSONObject jsonProductObject = arr.getJSONObject(i);
  String name = jsonProductObject.getString("name");
  String url = jsonProductObject.getString("url");


}
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did you try this? –  TharakaNirmana Sep 24 '13 at 9:16
 
Im having a hard time getting my JSONstring from URL. Maybe you could help with that? –  Stebra Sep 24 '13 at 10:49
 
Send me the URL –  TharakaNirmana Sep 24 '13 at 11:00
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up vote 2 down vote 
public static void main(String[] args) throws JSONException {
    String str = "[{\"name\":\"name1\",\"url\":\"url1\"},{\"name\":\"name2\",\"url\":\"url2\"}]";

    JSONArray jsonarray = new JSONArray(str);


    for(int i=0; i<jsonarray.length(); i++){
        JSONObject obj = jsonarray.getJSONObject(i);

        String name = obj.getString("name");
        String url = obj.getString("url");

        System.out.println(name);
        System.out.println(url);
    }   
}

Output:

name1
url1
name2
url2
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