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I'd like to get urls in strings. For example I got:

"You got to see this link[http://some.link/you/have?to=see]"

I think theses are non-valid url characters: "'()[]{}

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Can you please clarify more on your question and show us what you've tried until now? –  Allendar Mar 9 at 18:14
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They are valid URL characters. Is your strings all include URLs between square brackets [] or is it just an example? –  Selcuk Mar 9 at 18:15
    
@Selcuk This is just an example –  lanodan Mar 9 at 18:20
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1 Answer 1

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Your regex to find the URL would look something like this:

'https?://[^\"\'\(\)\[\]\{\}]+'

which is basically just looking for a string starting with 'http' or 'https' and then '://' and then all characters that follow that are not "'()[]{}

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Not working with: "You got to see this link[http://some.link/you/have?to=see]".split('https?://[^\"\'\(\)\[\]\{\}]+') Maybe I've to use re.compile ? –  lanodan Mar 9 at 18:28
    
try re.findall('https?://[^\"\'\(\)\[\]\{\}]+', "You got to see this link[http://some.link/you/have?to=see]")[0] this works for me, just tried it –  SS781 Mar 9 at 20:51
    
Did this work for you? –  SS781 Mar 10 at 15:29
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