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I want to pass a array of array from javascript into php. what is the simplest way to do it?

Array in javascript likes:

var resultArray = [ 
                    {"id":"1", "description":"aaa", "name":"zzz", "titel":"mmm"},
                    {"id":"2", "description":"bbb", "name":"yyy", "titel":"nnn"},
                    {"id":"3", "description":"ccc", "name":"xxx", "titel":"lll"},
                    {"id":"4", "description":"ddd", "name":"www", "titel":"qqq"},
                    {"id":"5", "description":"eee", "name":"vvv", "titel":"rrr"}
                  ] 

windows.location.href = "searchResults.php?resultArray=" + JSON.stringify(resultArray);

in the php I use:

$resultArray = json_decode($_GET['resultArray']);

echo $resultArray[0]['id']; // should be "1", but show nothing

Thanks in advance for every reply!

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3 Answers

up vote 0 down vote accepted 
Its json_decode() not json.decode()

$resultArray = json_decode($_GET['resultArray']);

if you print_r($resultArray) you will get a standard class array and you can access it by echo $resultArray[0]->id and will give you 1;

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yes, it works. thanks –  cecilfang May 3 '13 at 12:57
 
Yuo are welocme @cecilfang –  웃웃웃웃웃 May 3 '13 at 13:02
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up vote 2 down vote

json_decode will create objects for objects encoded as JSON. If you want an associative array instead, pass true as second argument:

$resultArray = json_decode($_GET['resultArray'], true);

Reference: http://php.net/manual/en/function.json-decode.php

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yes, it works. thanks –  cecilfang May 3 '13 at 12:58
 
why can I not choose the both solutions as the answer _, sry! –  cecilfang May 3 '13 at 13:11
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up vote 0 down vote

It's json_decode, not json.decode

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sry, it was typo –  cecilfang May 3 '13 at 12:54
 
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. –  Shikiryu May 3 '13 at 13:08
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