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up vote 3 down vote favorite
1

I have a bash script with doing lot of things called script.sh:

#!/bin/bash
#It
#Is
#Doing
#Things

Is there a way that I be able to get the proccess of script and then kill it after 5 minutes?

Like:

#!/bin/bash
#Now here give pid of script.sh then kill it after 5 minutes
#It
#Is
#Doing
#Things

update

Imagin I have this script:

#!/bin/bash
while :
do
      echo "line printed"
done

If we use these answers it doesn't show the output...

I want out put be printed and after 5 minutes cntrl + c signal kill the process of bash...

Is this good idea?

PID=$$
kill -SIGINT $PID

Where should be put?

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3  
mywiki.wooledge.org/XyProblem ;) –  n.st 14 hours ago
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3 Answers

up vote 9 down vote

You get the PID with PID=$$.

What you want may be most easily achieved with the command timeout.

But you can run a background process, too:

(sleep $TIMEOUT && kill "$PID") &
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Pardon but there is a problem..while my script is running it shows me output..but in your case this is not do that..Imagin you have infinitive while loop that echo sth...when I do what you said it doesn't show me output and my machine hangs... –  MortezaLSC 11 hours ago
    
@MortezaLSC I have given you two suggestions. What exactly have you done? –  Hauke Laging 8 hours ago
    
see Gnouc's answer, This is my script and please see my update as well..Thank you very much –  MortezaLSC 8 hours ago
    
You see...It brings my script to background...while my script is running it shows sth in terminal runtime.. –  MortezaLSC 8 hours ago
1  
I think you still need to add & at the end to actually send it to the background. The brackets only start a subshell. –  Darkhogg 5 hours ago
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up vote 8 down vote

The timeout utility that is a part of GNU coreutils does it for you:

timeout 5m bash script.sh

would terminate the script after 5 minutes of execution.

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Pardon but there is a problem..while my script is running it shows me output..but in your case this is not do that..Imagin you have infinitive while loop that echo sth...when I do what you said it doesn't show me output and my machine hangs... –  MortezaLSC 11 hours ago
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up vote 4 down vote

You can use a check condition:

#!/bin/bash

START=$(date +%s)

while [[ $(($(date +%s) - $START)) -ne 300 ]]
do
    #do something here
done

echo QUIT

Explanation

  • date +%s get the time in seconds since epoch, we save it to START variable, mark start time of script.
  • [[ $(($(date +%s) - $START)) -ne 300 ]]: we get current time (date +%s again) subtract to start time (which is saved in START variable).
  • If the result is not equal 300 (5 minutes), script continue running,
  • If the result is equal 300, meaning script has run 5 minutes since start time, we quit the while loop, script ends.
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Thank you..My script has infinitive loop...if I put my whole script into your while loop do you think it works? Thank you –  MortezaLSC 8 hours ago
    
I think you must use my while loop instead of your infinitive loop to make it works. Can you give more details about your script? –  Gnouc 8 hours ago
    
+1 This is my script –  MortezaLSC 8 hours ago
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