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I have following set of an array

array('www.example.com/','www.example.com','www.demo.example.com/','www.example.com/blog','www.demo.com');

and I would like to get all element which matching following patterns,

$matchArray  = array('*.example.com/*','www.demo.com');

Expected result as 

array('www.example.com/','www.demo.example.com/','www.example.com/blog','www.demo.com');

Thanks :)

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2 Answers

up vote 1 down vote accepted

This works:

    $valuesArray = array('www.example.com/','www.example.com','www.demo.example.com/','www.example.com/blog','www.demo.com');
    $matchArray  = array('*.example.com/*','www.demo.com');
    $matchesArray = array();

    foreach ($valuesArray as $value) {
        foreach ($matchArray as $match) {

            //These fix the pseudo regex match array values
            $match = preg_quote($match);
            $match = str_replace('\*', '.*', $match);
            $match = str_replace('/', '\/', $match);

            //Match and add to $matchesArray if not already found
            if (preg_match('/'.$match.'/', $value)) {
                if (!in_array($value, $matchesArray)) {
                    $matchesArray[] = $value;
                }
            }

        }
    }

    print_r($matchesArray);

But I would reccomend changing the syntax of your matches array to be actual regex patterns so that the fix section of code is not required.

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thank you so much :) –  abhis Mar 6 '12 at 9:49
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up vote 0 down vote 
/\w+(\.demo)?\.example\.com\/\w*|www\.demo\.com/

regexr link

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