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up vote 1 down vote favorite

I'm having great trouble passing some information from my Angularjs code to my PHP code for processing.

JS

Controller 

var dataString = '{"round": {"number": 1,"drops": [{"pos": "0","cust": 1025}]}}';
dropService.updateDrops(dataString)
    .success(function(data) {
        console.log(data);
})

Service

updateDrops : function(drops) {
        return $http({
            url: "/app/php/update_rounds.php",
            method: "POST",
            data: drops,
            headers: {'Content-Type': 'application/x-www-form-urlencoded'}
        });
    }

PHP

$dropString = $_POST;

$dropArray = json_decode($_POST);
$a = $dropArray->{"round"}->{"number"};

echo "Round = ".$a;

What I expect to see on the console is

Round = 1

but what I get is

Round =

Obviously something is going screwy. However if I replace

$dropString = $_POST;

with

$dropString = '{"round": {"number": 1,"drops": [{"pos": "0","cust": 1025}]}}';

everything works out just fine so I know that the PHP will work if I can just get the right data to it. Where am I going wrong?

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1  
$_POST is a PHP array with all posted values. Try var_dump($_POST); to check which your data uses or provide one in your AJAX request that you use specifically –  kingkero 15 hours ago
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1 Answer

up vote 2 down vote accepted

$_POST is an array of key=>value pairs

You're looking for the entire POST BODY as a string. Use this:

$dropString = http_get_request_body();

Edit: If that doesn't work, use

$dropString = file_get_contents('php://input');
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2  
Might want to make a note that this is only available in pecl_http, otherwise just use file_get_contents('php://input') –  Phil 15 hours ago
 
Good call, @Phil. –  Tommy Crush 15 hours ago
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