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up vote 0 down vote favorite

I have this code:

$node = new Node();

Now I want to make the 'Node' object dynamic
I get the dynamic name from my config class, this works: 

$var = Config::instance('modules/activities/config')->get('className');
$node = new $var();

But how can I write this in 1 line?
This doensn't work:

$node = new Config::instance('modules/activities/config')->get('className')();
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4 Answers 4

up vote 1 down vote

This a new language feature as of PHP 5.4

Class member access on instantiation has been added, e.g. (new Foo)->bar()

See http://docs.php.net/manual/en/migration54.new-features.php

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1  
thanks but I'm using 5.2, good to know this for the future –  Ruben Sep 5 '12 at 13:55
up vote 0 down vote

If you modify the instance method so it returns the object you should be able to use that syntax. Something like :

public static function instance()
{
    if (!self::$instance)
        self::$instance = new new Config();
    return self::$instance;
}
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up vote 0 down vote accepted

My colleague helped my out, I made a static function in my helper class:

public static function factory($name = '',  $var = NULL)
{
    $object = new $name((isset($var)) ? $var : '');
    return $object;
}

now this is my code (looks a bit messy maybe):

$node = Helper::factory(Config::instance('modules/activities/config')->get('className'), $var);
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But how are you going to pass arguments to your constructor? –  Ja͢ck Sep 5 '12 at 14:23
    
good point, I changed it –  Ruben Sep 6 '12 at 6:35
    
You could look into ReflectionClass::newInstance() as well –  Ja͢ck Sep 6 '12 at 11:15
up vote -4 down vote

Simple. To write them in 1 line just don't use a line break between them like so:

$var = Config::instance('modules/activities/config')->get('className');$node = new $var();
share|improve this answer
    
you sir are a genius –  Ruben Sep 5 '12 at 13:54
1  
I think he wanted to simplify things, not literally jam all of the lines together. –  Brad Sep 5 '12 at 13:54

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