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up vote 0 down vote favorite

I want to output only 1 name data from my array which is: 

Array
(
    [results] => Array
      (
        [0] => Array
            (
                [0] => some name
                [1] => Founder
            )

        [1] => Array
            (
                [0] => some name
                [1] => Marshal
            )

        [2] => Array
            (
                [0] => some name
                [1] => Marshal
            )

        [3] => Array
            (
                [0] => some name
                [1] => Royal Knight
            )

        [4] => Array
            (
                [0] => some name
                [1] => Knight
            )
    )

)
1

now I use :

echo "<pre>";
echo print_r($API->getSearchFreeCompanyMembers());
echo "</pre>";

to print the array which seems to work fine but when I try selecting single array like: 

echo "<pre>";
echo print_r($API->getSearchFreeCompanyMembers(1)[0]);
echo "</pre>";

all I get is 1 on the page

Any help would be much appreciated, if any more code needed please let me know.

share|improve this question
    
How come you changed getSearchFreeCompanyMembers() to getSearchFreeCompanyMembers(1) ? –  Ronni Skansing Oct 4 '13 at 12:11
1  
Can you explain what getSearchFreeCompanyMembers() does and how parameters affect output? –  erKURITA Oct 4 '13 at 12:11
    
$API->getSearchFreeCompanyMembers[1][0] –  User8889 Oct 4 '13 at 12:12
    
You can accept one answer at a time but it's ok :-). –  Sheikh Heera Oct 4 '13 at 12:24
    
thank you all for the great answers been a great help –  user2754055 Oct 4 '13 at 12:47
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4 Answers

up vote 0 down vote accepted 
echo "<pre>";
$members = $API->getSearchFreeCompanyMembers();
print_r($members['results'][0]); //no echo needed
echo "</pre>";
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up vote 2 down vote

You seem to have changed the arguments when calling the method. getSearchFreeCompanyMembers

Your first example shows getSearchFreeCompanyMembers() The second is getSearchFreeCompanyMembers(1)

To get the first element in the array returned by the method.

1. Dereference as you did (just do not put 1 as argument).

$result = $API->getSearchFreeCompanyMembers()[0]

Beware the side effect is that the rest of the array returned is discarded. Also this feature is only available from <= 5.4

2. Save the returned array to a variable and pick the first element

$array = $API->getSearchFreeCompanyMembers();
print_r($array[0]);

For more info on arrays and for dereference see example #7 http://php.net/manual/en/language.types.array.php

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up vote 1 down vote

You may try something like this

$array = $API->getSearchFreeCompanyMembers();
echo $array['results'][0][1]; // first name (Founder)
echo $array['results'][1][1]; // second name (Marshal)

Or, use (for some name)

echo $array['results'][0][0]; // first ('some name')
echo $array['results'][1][0]; // second ('some name')

Here, results is an associative array and the first array is [0] and every array ([0], [1]) in results contains an array. So, it's something like this

$array = Array(
    'results' => Array (
        Array ( 'some name', 'Founder' ), // 1st array in results
        Array ( 'some name', 'Marshal' )  // 2nd array in results
    )
);
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up vote 0 down vote

like to print array results key [0] value [1] i.e founder. you have to call array like this
before print_r there is no need of echo

        echo "<pre>";
        print_r($results [0][0]);
        echo "</pre>";

similarly for 

 echo "<pre>";
$employee=$API->getSearchFreeCompanyMembers();
print($employee['results'][1][0]);
echo "</pre>";
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