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I set x is array contains several variables with are inputs of a evaluation function. Each variable has limit defined in xBoundary[index][min,max]. Each possible variable value has step size xStep[].

e.g. x[0] is between 0 and 10 since xBoundary[0][0]=0 and xBoundary[0][1]=10. xStep[0]=0.5 then x has possible value 0,0.5,1,1.5,.....9.5,10. How can I access all possible value of x? I think this is a n dimensional array where n = length of x.

The following is my code. It is infinite loop.

#include <stdio.h>

#define nx_SIZE 2                   // dimension of x

double x[nx_SIZE] = {0};                     // Initialize x
double xBoundary[nx_SIZE][2]={{0,5},{2,5}};  //Contains lower and upper boundary of x.
                                             //xBoundary[][0]=min
                                             //xBoundary[][1]=max
double xStep[nx_SIZE]={1};                   //Step size for variable in x.

void iterate(int dimension) {


  int i = dimension - 1;
  double currentX, upperLimit;

  if (i == -1){

    printf("x: %f %f \n", x[0], x[1]);
    //evaluate();

  } else {

    currentX = xBoundary[i][0];
    upperLimit = xBoundary[i][1];

    while (currentX < upperLimit){
      x[i] = currentX;
      iterate(i);
      currentX = currentX + xStep[i];
    } //End of while

  }
}

int main (){

  iterate(nx_SIZE);

  return 1;
}
share|improve this question
    
For starters, 1. Format your code, 2. declare xBoundary as xBoundary[nx_SIZE][2]={{0,5},{2,5}}; 3. There is a variable demantion undeclared in your function –  brokenfoot Mar 20 at 6:46
    
Thanks. I edited the typo and format. @brokenfoot –  Dan Mar 20 at 6:58

2 Answers 2

up vote 0 down vote

Based on your requirement, this is just a sample loop of nxSize times. try the code below(I didn't test it, you might need some updates on it)

int i;
for (i = 0; i < nx_SIZE; i++) {
    int v;
    for (v = xBoundary[i][0]; v <= xBoundary[i][1]; v += xStep[i]) {
        printf("%f", v);
    }
    printf("\n");
}

the code above was based on nx_SIZE = 2 which is in your example, if nxSIZE is another value, you should intialize xBoundary correctly in order to make it work.

share|improve this answer
up vote 0 down vote accepted

I found the problem is caused by double xStep[nx_SIZE]={1};. This only assign xStep[0] value to 1 and rest are 0. The zero increment cause infinite loop.

Value of x is n dimensional array where n = length of x.

#include <stdio.h>

#define nx_SIZE 2                              // dimension of x

double x[nx_SIZE] = {0};                       // Initialize x
double xBoundary[nx_SIZE][2]={{0,5},{2,5}};    //Contains lower and upper boundary of x.
                                               //xBoundary[][0]=min
                                               //xBoundary[][1]=max
double xStep[nx_SIZE]={1,1};                   //Step size for variable in x.
int counter = 0;                               //Number of possible x

void iterate(int dimension) {

  int i = dimension - 1;
  double currentX;

  if (i == -1){
    printf("x: %f %f \n", x[0], x[1]);
    counter++;
  } else {

    for (currentX = xBoundary[i][0]; currentX <= xBoundary[i][1]; currentX += xStep[i]) {
      x[i] = currentX;
      iterate(i);
    }

  } //End of if
} // End of iterate

int main (){

  iterate(nx_SIZE);
  printf("counter: %d", counter);
  getchar();

  return 1;
}
share|improve this answer

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