Top new questions this week:
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Zermelo's Theorem, when applied to chess, states:
"either white can force a win, or black can force a win, or both sides can force at least a draw [1]"
I do not get this. How can it be proven?
…
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I am doing landscaping and some times I need to create circles or parts of circles that would put the centre of the circle in the neighbours' garden, or there are other obstructions that stop me from …
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We've just been learning about complex numbers in class, and I don't really see why they're called numbers.
Originally, a number used to be a means of counting (natural numbers).
Then we extend …
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Let us define $\{a_n\}$ as $a_1=a_2=1$,$$a_{n+2}=a_{n+1}+\frac{a_n}{2}\ \ (n=1,2,\cdots).$$
Then, is the following true?
If $a_n$ is an integer, then $n\le 8$.
I conjectured this by using …
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Does there exist two non-constant polynomials $f(x),g(x)\in\mathbb Z[x]$ such that for all integers $m,n$, gcd$(f(m),g(n))=1$?
I think there are no such polynomials, but how to prove?
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So you start with a 1-dimensional stick, remove the middle third of it, leaving 2 pieces. From each of these 2 pieces, remove the middle third. Etc. Whatever is left at the end of infinitely many …
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This is what I did for:
$$\lim \limits_{x \to \infty} {\left({3x-2 \over3x+4}\right)}^{3x+1}$$
Check form: $\left({\infty \over \infty}\right)^{\infty}$.
Apply L'Hospital's Rule to just $\lim …
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Greatest hits from previous weeks:
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Let cost price of an item be $C$, selling price be $S$. Assume the seller gets benefited.
Then, Profit, $P = S - C$.
Now, What is formula for calculating Profit Percent?
$P \% = \dfrac{P}{C} …
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What are some surprising equations / identities that you have seen, which you would not have expected?
This could be complex numbers, trigonometric identities, combinatorial results, algebraic …
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Can you answer these?
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Question:
let matrix $A,B,C\in M_{n}(C)$ is Hermitian matrix and is Positive definite matrices
,such $$A+B+C=I_{n}$$show that
$$\det\left(6(A^3+B^3+C^3)+I_{n}\right)\ge …
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Question $1$:
Is
$\frac{1}{\pi}\arccos\left(\frac{{\sqrt{2*\sqrt{2*\sqrt{2}*...n}}}}{2}\right)$
always a rational number when each$*$ is either $+$ or $-$ and $n$ may or may not be infinite?
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How would one compute the units in $\mathbb{Z}[\sqrt[4]2]$? According to one source, it can be shown that the fundamental units are $1 + \sqrt[4]2$ and $1 + \sqrt{2}$, but it does not specify the …
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