See if Strings are shared in Java : String « Data Type « Java

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Java » Data Type » String 




See if Strings are shared in Java
     
/*
 * Copyright (c) Ian F. Darwin, http://www.darwinsys.com/, 1996-2002.
 * All rights reserved. Software written by Ian F. Darwin and others.
 * $Id: LICENSE,v 1.8 2004/02/09 03:33:38 ian Exp $
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 * modification, are permitted provided that the following conditions
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 *    notice, this list of conditions and the following disclaimer.
 * 2. Redistributions in binary form must reproduce the above copyright
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 *    documentation and/or other materials provided with the distribution.
 *
 * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS''
 * AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED
 * TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR
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 * Java, the Duke mascot, and all variants of Sun's Java "steaming coffee
 * cup" logo are trademarks of Sun Microsystems. Sun's, and James Gosling's,
 * pioneering role in inventing and promulgating (and standardizing) the Java 
 * language and environment is gratefully acknowledged.
 
 * The pioneering role of Dennis Ritchie and Bjarne Stroustrup, of AT&T, for
 * inventing predecessor languages C and C++ is also gratefully acknowledged.
 */


/**
 * See if Strings are shared in Java.
 * The thing is, it depends on whether you say 
 * "string" or new String("mystring");
 */
public class TwoStrings {
  public static void main(String[] argv) {
    String one = "A String";
    String two = "A String";
    String three = new String(one);
    compare(one, two);
    compare(two, three);
  }
  public static void compare(String one, String two) {
    System.out.println("Comparing...");
    if (one == two) {
      System.out.println("Strings are shared: " +
        one.hashCode() ", " + two.hashCode());
    else if (one.equals(two)) {
      System.out.println("At least the strings are equal: " +
        one.hashCode() ", " + two.hashCode());
      System.out.println((Object)one);
      System.out.println(two);
    else System.out.println("This is rather distressing, sir.");
    System.out.println();
  }
}



           
         
    
    
    
    
  














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