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up vote 16 down vote favorite
9

I have array made by function .push. In array is very large data. How is the best way send this to PHP script?

   dataString = ??? ; // array?
   $.ajax({
        type: "POST",
        url: "script.php",
        data: dataString, 
        cache: false,

        success: function(){
            alert("OK");
        }
    });

script.php:

  $data = $_POST['data'];

  // here i would like use foreach:

  foreach($data as $d){
     echo $d;
  }

How is the best way for this?

share|improve this question

5 Answers 5

up vote 27 down vote accepted

Encode your data string into JSON.

dataString = ??? ; // array?
var jsonString = JSON.stringify(dataString);
   $.ajax({
        type: "POST",
        url: "script.php",
        data: {data : jsonString}, 
        cache: false,

        success: function(){
            alert("OK");
        }
    });

In your PHP

$data = json_decode(stripslashes($_POST['data']));

  // here i would like use foreach:

  foreach($data as $d){
     echo $d;
  }

Note

When you send data via POST, it needs to be as a keyvalue pair.

Thus

data: dataString

is wrong. Instead do:

data: {data:dataString}

share|improve this answer
5  
Why use JSON.stringify? What's wrong with just data: {data: dataString}? –  Rocket Hazmat Jul 12 '12 at 15:54
    
@Rocket: I suppose you could do that as well in which case Jquery would serialize the array. –  xbonez Jul 12 '12 at 16:59
4  
Then you wouldn't need json_decode, $_POST['data'] would already be an array. –  Rocket Hazmat Jul 12 '12 at 17:01
    
Friendly reminder to always validate your post values throwing them around. –  citizen conn Oct 21 '13 at 1:55
up vote 0 down vote

This is a link that might usefull for you Posting Array to PHP using ajax and agree with Vyktor i've tried it and works great,

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3  
While this link may answer the question, it is better to include the essential parts of the answer here and provide the link for reference. Link-only answers can become invalid if the linked page changes. –  Szymon Jan 6 at 4:04
up vote 1 down vote

dataString suggests the data is formatted in a string (and maybe delimted by a character).

$data = explode(",", $_POST['data']);
foreach($data as $d){
     echo $d;
}

if dataString is not a string but infact an array (what your question indicates) use JSON.

share|improve this answer
    
dataString this is only example. I dont must use this, but i dont know what i must use –  Paul Attuck Jan 25 '12 at 11:04
    
data: { id_arr: [array variable goes here]}, will be accessible as $_POST['id_arr'] as an array in PHP –  bromelio Jun 24 at 14:37
up vote 2 down vote

Data in jQuery ajax() function accepts anonymous objects as its input, see documentation. So example of what you're looking for is: 

dataString = {key: 'val', key2: 'val2'};
$.ajax({
        type: "POST",
        url: "script.php",
        data: dataString, 
        cache: false,

        success: function(){
            alert("OK");
        }
    });

You may also write POST/GET query on your own, like key=val&key2=val2, but you'd have to handle escaping yourself which is impractical.

share|improve this answer
    
This didn't work for me, however data: { id_arr: [array variable goes here]} will be accessible as array $_POST['id_arr'] in PHP –  bromelio Jun 24 at 14:38
up vote 5 down vote 
 dataString = [];
   $.ajax({
        type: "POST",
        url: "script.php",
        data:{data: $(dataString).serializeArray()}, 
        cache: false,

        success: function(){
            alert("OK");
        }
    });

http://api.jquery.com/serializeArray/

share|improve this answer
    
and how can i next read this in PHP file? –  Paul Attuck Jan 25 '12 at 11:02
1  
Since serializeArray works by creating a JSOn string, you would first need to use json_decode on the PHP side –  xbonez Jan 25 '12 at 11:34
2  
I'd suggsst dropping serializeArray, and just doing data: {data: dataString}. Then $_POST['data'] will be an array. –  Rocket Hazmat Jul 12 '12 at 15:55

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