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up vote -1 down vote favorite

I have defined the following integer array: $myArray = range(0, 3);

The in_array("1", $myArray); returns false ?

How to convert the integer $myArray into a string array ?

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6  
You sure about that? –  Tim Cooper Jun 21 '11 at 15:41
2  
in_array doesn't do strict type checking unless you specify it in the third parameter - there's something else going on. –  Jimmy Sawczuk Jun 21 '11 at 15:41
2  
Cannot reproduce: $myArray = range(0,3); var_dump("1", $myArray); returns true on my system (PHP5.3.5). It seems, that you are doing something else wrong. –  KingCrunch Jun 21 '11 at 15:42
2  
@Stef - I've copied those exact 2 line into a test script and it returns bool(true) when I var_dump the in_array function's result. –  Francois Deschenes Jun 21 '11 at 15:42
1  
Cannot reproduce the problem: codepad.org/NmJWFAxh –  Felix Kling Jun 21 '11 at 15:43

3 Answers 3

up vote 2 down vote accepted

in_array has 3rd parameter $strict, but it is false by default.

$myArray = range(0, 3);
print_r($myArray);

var_dump(in_array("1", $myArray, false));

Array ( [0] => 0 1 => 1 [2] => 2 [3] => 3 ) bool(true)

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up vote 2 down vote 
$myArray = array_map('strval',$myArray);

strval
array_map

As others pointed out though, it works as-is

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If his code does not work, converting the elements to strings won't either. –  Felix Kling Jun 21 '11 at 15:44
1  
@FelixKling: Agreed, just assume post the answer to the original question though. I also have updated with the code to show before/after cast to disqualify that being the problem. –  Brad Christie Jun 21 '11 at 15:47
up vote 1 down vote

IT 100% works for me

<?php print_r(range(0,3));
$g = range(0,3);
echo in_array("1",$g);

returns

Array ( [0] => 0 [1] => 1 [2] => 2 [3] => 3 ) 1
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