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I'm trying to use css selector to get an element inside a <li> with Selenium

That's I have:

<div id= "popup">
  <ul>
     <li>
        <div id="item" option= "1" ....> </div>
     </li>
     <li>
        <div id="item" option= "2" ....> </div>
     </li>
  </ul>
 </div>

I need to get the second div, with option=2. I tried:

webdriver.findElement(By.cssSelector("#popup > ul li:nth-child(n) [option=2]");

that works fine in console of Chrome but not with Selenium :/ What's wrong with this?

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2 Answers

up vote 1 down vote

Two issues:

  • :nth-child(n) means "any value of n" which will result in every child being matched. You probably mean to use :nth-child(2) if you want to make sure you only get the element under the second li. Or if it doesn't matter which li it appears in, you can get rid of the :nth-child() selector entirely.

  • The value in an attribute selector must be quoted if it begins with a digit, so [option='2'].

The correct selector, therefore, is:

webdriver.findElement(By.cssSelector("#popup > ul li:nth-child(2) [option='2']");
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Yeah "#popup > ul li:nth-child(2) [option='2']" work´s fine, but i need select element with [option='2'] but i dont know position in the list. :nth-child() does not work. Finaly i use: "#popup > ul li [option='2']" and works fine in console and selenium –  bott Jun 11 at 7:20
    
@bott: I did mention that in my answer. I knew I should have added the other option to go with the explanation just in case... –  BoltClock♦ Jun 11 at 7:22
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up vote 0 down vote

Using:

"#popup > ul li [option='2']"

works fine in console and selenium!

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