php preg_replace regex to replace function type string with its parameters [closed]

Question

I've text for example.

a quick brown fox sance("jumps") over a lazy ok("good") dog.

I want to remove sance() from the above string but inside text. so the output will look like

a quick brown fox "jumps" over a lazy ok("good") dog.

i tried too many regex to remove only sance() but have no luck. most of the time it replaces other ok("good") which is not acceptable.

can somebody plz help me?

Answer 1

Try this one:

$string = 'a quick brown fox sance("jumps") over a lazy ok("good") dog.';

echo preg_replace('/sance\((.*?)\)/', '$1', $string);

Output

a quick brown fox "jumps" over a lazy ok("good") dog.

Answer 2

$pattern = "/sance\((\S+)\)/";
$replace = "\1";
$input_lines = 'a quick brown fox sance("jumps") over a lazy ok("good") dog.';

preg_replace($pattern, $replace , $input_lines);

try it