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up vote 118 down vote favorite
23

Is it possible to return a dynamic object from a json deserialization using json.net? I would like to do something like this:

dynamic jsonResponse = JsonConvert.Deserialize(json);
Console.WriteLine(jsonResponse.message);
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Looks like a duplicate of stackoverflow.com/questions/3142495/… –  Jon of All Trades Feb 15 '13 at 15:47
4  
Not a duplicate, he's asking specifically about json.net and your linked question is just asking for any solution at all. –  T.W.R.Cole Sep 27 '13 at 20:37
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5 Answers 5

up vote 150 down vote accepted

latest json.net version allow do this:

dynamic d = JObject.Parse("{number:1000, str:'string', array: [1,2,3,4,5,6]}");

Console.WriteLine(d.number);
Console.WriteLine(d.str);
Console.WriteLine(d.array.Count);

output:

 1000
 string
 6

Documentation here: LINQ to JSON with Json.NET

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1  
Note that for arrays the syntax is JArray.Parse. –  jgillich May 15 at 10:24
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up vote 31 down vote

As of Json.NET 4.0 Release 1, there is native dynamic support:

[Test]
public void DynamicDeserialization()
{
    dynamic jsonResponse = JsonConvert.DeserializeObject("{\"message\":\"Hi\"}");
    Console.WriteLine(jsonResponse.message); // Hi
}

And, of course, the best way to get the current version is via NuGet.

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up vote 21 down vote

I know this is old post but JsonConvert actually has a different method so it would be

var product = new { Name = "", Price = 0 };
var jsonResponse = JsonConvert.DeserializeAnonymousType(json, product);
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6  
That would be deserializing a json payload into an anonymous type, not a dynamic type. Anonymous types and dynamic types are different things, and I don't believe this addresses the question asked. –  jrista Aug 1 '12 at 19:12
    
Is it necessary to use two variables? Why not reuse the first one in the second statement? –  RenniePet Jul 23 '13 at 1:06
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up vote 7 down vote

You need to have some sort of type to deserialize to. You could do something along the lines of:

var product = new { Name = "", Price = 0 };
dynamic jsonResponse = JsonConvert.Deserialize(json, product.GetType());

Note: My answer was based on a solution for .NET 4.0's build in JSON serializer.

Here is a link to deserialize to anonymous types is here:

http://blogs.msdn.com/b/alexghi/archive/2008/12/22/using-anonymous-types-to-deserialize-json-data.aspx

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up vote 0 down vote

Yes you can do it using the JsonConvert.Deserialize. To do that, just simple do:

dynamic jsonResponse = JsonConvert.Deserialize(json);
Console.WriteLine(jsonResponse["message"]);
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