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up vote 0 down vote favorite

I've search up and down but can't seem to get this array to function properly, I'm missing something simple but unable to figure out what exactly.

<?php

    $dates2 = 'Aug 30, 2013';
    $dates3 = 'Sep 13, 2013';

    $cards[0] = array(
        'card' => 'Discover',
        'pay'  => '875', 
        'when' => array('
            'Sep 03, 2013', 
            'Oct 03, 2013', 
            'Nov 03, 2013',
            'Dec 03, 2013'
        ),                    
    );
    $cards[1] = array(
        'card' => 'Visa',
        'pay'  => '375', 
        'when' => array(
            'Sep 23, 2013', 
            'Oct 23, 2013', 
            'Nov 23, 2013',
            'Dec 23, 2013'
        ),        
    );
    $cards[2] = array(
        'card' => 'Mastercard',
        'pay'  => '1025', 
        'when' => array(
            'Sep 12, 2013', 
            'Oct 13, 2013', 
            'Nov 13, 2013',
            'Dec 13, 2013'
        ),
    );
    $cards[3] = array(
        'card' => 'Amex',
        'pay'  => '650', 
        'when' => array(
            'Aug 25, 2013', 
            'Sep 05, 2013', 
            'Oct 25, 2013',
            'Nov 25, 2013'
        ),
    );

    for ($i=0; $i<=3; $i++){  
        if ($cards[$i]['when'][$i] > $dates2 && ($cards[$i]['when'][$i] < $dates3) or ($cards[$i]['when'][$i] == $dates2)) {
            print "<tr>
                <td>$cards[$i]['card']</td>
                <td><input class='amount' size='3' value='$cards[$i]['pay']'></td>
            </tr>";                                  
         } 
     }

?>

Output: Array['card'] Array['card'] Array['card'] Array['card']

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1  
Curious as to why it got a down vote? If you're going to downvote someone, you should provide feedback as to why. – Brant Aug 16 at 20:59

3 Answers

up vote 2 down vote

You need to concatenate the variables or reset them then print them.

DEMO PHPfiddle http://phpfiddle.org/main/code/ia5-dh6

This is with them reset

DEMO PHPfiddle http://phpfiddle.org/main/code/7if-nd3

note i have added the missing table tags too

$CardType = $cards[$i]['card'];
$Payment = $cards[$i]['pay'];

print "<tr>
         <td>$CardType</td>
         <td><input class='amount' size='3' value='$Payment'></td>
       </tr>";
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up vote 1 down vote

It's your output statement, this fixed it for me:

print "<tr><td>" . $cards[$i]['card'] . "</td><td><input class='amount' size='3' value='" . $cards[$i]['pay'] . "'></td></tr>";
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up vote 1 down vote

Reference: Variable parsing

Variable parsing

When a string is specified in double quotes or with heredoc, variables are parsed within it.

There are two types of syntax: a simple one and a complex one. The simple syntax is the most common and convenient. It provides a way to embed a variable, an array value, or an object property in a string with a minimum of effort.

The complex syntax can be recognised by the curly braces surrounding the expression.

Update:

Please read on "Simple Syntax" and especially on "Complex Syntax" for this particular case. 

print "<tr>
           <td>{$cards[$i]['card']}</td>
           <td><input class='amount' size='3' value='{$cards[$i]['pay']}'></td>
       </tr>";
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