PHP. Function preg_replace_callback with create_function() because PHPversion 5.2

Question

I want to replace identical <IMG> tags in a string with an array with different values. So IMG, IMG will be:

<IMG src="data:image/jpg;base64,/9j/4AA ....etc> , <IMG src="data:image/png;base64,/9j/4AA ....etc >

Since the pattern has to be mixed with preg_replace(), and because preg_replace_all doesn't exist, i have to use the function preg_replace_callback().

I have PHP version 5.2 so i have to use a create_function() within preg_replace_callback().

Does anybody have an idea how preg_replace_callback() has to look like in this situation? I cannot understand how create_function works. Do i have to make a loop or something?

My code with preg_replace(): This changes all IMG tags with the first picture of the array. But i need loop through all the IMG tags with preg_replace_callback()/create_function() and replace with different pictures of the array.

$artikelinhoud = $simpleXml->StandaardOplossing->attributes()->ArtikelInhoud;
$arrayImages = array();
preg_match_all('<!\[(CDATA)\[\s*(.*?)\s*\]\]>', $artikelinhoud, $arrayImages);

$images = array(); 
foreach ($arrayImages[2] as $key => $image) {
    $images[$key] = 'src="data:image/jpg;base64,' . $image . '"';   
}

$imagesOld = array();
$imagesOld[] = '/type="(.*?)"/';

$artikelinhoud = preg_replace($imagesOld, $images , $artikelinhoud);

Variable $imagesold is always the same. And $images is an array with different values to put between tags.

The array $images looks like:

[0]=> string(26464) "src="data:image/jpg;base64,/9j/4A...etc
[1]=> string(23464) "src="data:image/jpg;base64,/9j/4A....etc

Greetz, Eric