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I have written a shell script that will take a parameter, pass that parameter to Java command. But I get error during the execution.

Here is the script:

#The script takes an input, the file name to be styled and executes the java program based on it

echo "Hello World"
echo "The parameter passed is $1"
cd ~/CStyler/java/
`javac Main.java`
`java Main $1`

The error I get:

Hello World
The parameter passed is hello
CStyler.sh: 7: CStyler.sh: The: not found
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Possible duplicate of this Q&A –  utrecht Sep 14 '14 at 16:21

1 Answer 1

up vote 1 down vote accepted

You can use the following code :

java YourApp "$1"

And run your code like this :

./app.sh your_argument
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Yup got it! So what are these `` for? –  subham soni Sep 14 '14 at 12:54
    
excuse me what ? –  Kasra AD Sep 14 '14 at 12:55
    
In some shell scripts they execute the ls command like this ls, I asked what does these `` do? –  subham soni Sep 14 '14 at 12:56
    
it do nothing for me ! –  Kasra AD Sep 14 '14 at 13:03
    
They are used like a variable for what a command returns, example cd `pwd` would cd to the current directory (which you are already in, but i couldn't think of an example). –  DisplayName Jan 23 at 15:35

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