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I have to pass a php json array into a javascript function's on click event.

BEFORE JSON ENCODE PHP ARRAY STRUCTURE:

Array
(
    [group_id] => 307378872724184
    [cir_id] => 221
)

AFTER JSON ENCODE ARRAY STRUCTURE:

{"group_id":"307378872724184","cir_id":"221"}

The php json array looks like:

if(!empty($cirGrpArr))

   $jsonGrpArr = json_encode($cirGrpArr);

I need to pass the same into a javascript on click function like below:

<span onclick="Login(this,JSON.stringify('<?php echo $jsonGrpArr; ?>'))">click here</span>

The php json array is available in this page but how to pass it on click function so that i can iterate this json array to do some other stuff.

share|improve this question
1  
Why do people insist on writing JavaScript as java-script?! Nowhere, not in any documentation, or any half-decent tutorial, is it written that way. And yet it's a very common error here on SO. –  T.J. Crowder Dec 10 '13 at 12:23
    
A JSON string is in itself valid javascript. When the string is printed it can be iterated as an array, or an object if it contains key/value pairs. –  Flosculus Dec 10 '13 at 12:24
    
What is $jsonGrpArr? Don't show us PHP when you have a question about JavaScript. Show us the generated code that is sent to the browser. –  Quentin Dec 10 '13 at 12:33
    
What a convoluted way of assigning data to an event: make php print out html code with javascript inside it, make javascript dynamic by passing it json encoded php variables... all in one line. This will be a nightmare when the time for maintenance comes –  hanzo2001 Dec 10 '13 at 12:43
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1 Answer

up vote 0 down vote 
<span onclick="Login(this,'<?php echo $jsonGrpArr; ?>')">click here</span>

and 

function Login(e, jsonString){
var data = JSON.parse(jsonString);
}
share|improve this answer
    
but when i try to debug data via console.log(), its throwing Uncaught SyntaxError: Unexpected token ILLEGAL in console. any idea? –  George Joffin Joy Dec 10 '13 at 12:30
    
I am sorry I was using jQuery, updated answer check now. –  Bilal Dec 10 '13 at 12:31
    
i am getting e as this object.. but when trying to debug data after parsing it is showing unexpected token error... –  George Joffin Joy Dec 10 '13 at 12:33
    
in <?php echo $jsonGrpArr; ?> I am assuming this a json string. If not then encode using json_encode() in php –  Bilal Dec 10 '13 at 12:36
    
actually i have encoded it using json_encode –  George Joffin Joy Dec 10 '13 at 12:40
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