php array vote by values in array

Question

i have an array with many values and i want to get one value is many show of all values. Like this.

my array

$allValues = array(0,1,1);         // i want to get 1, because two 1 vs one 0

// other example
$allValue = array(0,0,0,1,1);      // I want to get 0, because three 0 vs two 1

// other example
$allValues = array(0,1);           // I want to get 0, because one 0 vs one 1 is 50:50 but 0 is first value

Sorry for my bad english.

Answer 1

<?php
$allValues = array(0,1,1);   

$result=array_count_values($allValues);   // Count occurrences of everything
arsort($result);                          // Sort descending order
echo key($result);                        // Pick up the value with highest number
?>

Edit: I've used key() because you are interested in knowing the value which has most number of occurrences and not the number itself. If you just need the number you can remove key() call.

Fiddle

Answer 2

try this

$allValues = array(0,0,0,1,1); 
$count = array_count_values($allValues);
echo $val = array_search(max($count), $count);

Answer 3

Works only with 0s and 1s

function evaluateArray($array) {
    $zeros = 0;
    $ones  = 0;

    foreach($array as $item) {
        if($item == 0) {
            $zeros++;
        } else {
            $ones++;
        }
    }
    // Change this if you want to return 1 if the result is equal
    // To return ($ones >= $zeros) ? 1 : 0; 
    return ($zeros >= $ones) ? 0 : 1;
}

Answer 4

Try this:

function find_value($array) {
    $zeros = 0;
    $ones = 0;
    for($i = 0; $i < count($array); $i++) {
        ($array[$i] == 0) ? $zeros++ : $ones++;
    }
    if($zeros == $ones) return $array[0];
    return ($zeros > $ones) ? 0 : 1;
}

Answer 5

you can use array_count_values — Counts all the values of an array

<?php
$array = array(1, "hello", 1, "world", "hello");
print_r(array_count_values($array));
?>

Output

Array ( [1] => 2 [hello] => 2 [world] => 1 )