current community

your communities

more stack exchange communities

Stack Exchange
tour help
careers 2.0
Take the 2-minute tour ×
Stack Overflow is a question and answer site for professional and enthusiast programmers. It's 100% free, no registration required.
up vote 1 down vote favorite

I'm trying to scatter or plot 2 sets of arrays using numpy and matplotlib. Everything is ok with the code except when I try to have lines instead of dots in my plot The plot is ok when I use :

from numpy import *
import matplotlib.pyplot as plt
positions=open('test.txt','r')

lines=positions.readlines()

for i in range(0,len(lines)):
    line=lines[i] 
    values=line.split("     ")

    x_val = [float(values[0])]
    y_val = [float(values[1])]
   # plt.scatter(x_val,y_val)
    #Or
    plt.plot(x_val,y_val,'ro')
    plt.title(' Data')
    plt.xlabel('x ')
    plt.ylabel('y')
    plt.show()

positions.close()

enter image description here

But when I replace plt.plot(x_val,y_val,'ro') with plt.plot(x_val,y_val,'r') , or plt.plot(x_val,y_val,'-') What I get is merely a blank page! enter image description here I have no idea what the problem is, because I tried it with many many different options and yet the only option which works properly is having 'o'.

share|improve this question

1 Answer 1

up vote 2 down vote accepted

The reason that you see no lines when you ask for a plot without setting the markers is because you are plotting each (x,y) point individually, which can have a point position, but would create a line of length zero.

If instead of plotting each point immediately upon reading it, you put those values into an array, and called the plot function just once, you could also show a line:

x_vals = []
y_vals = []

for i in range(0,len(lines)):
    line=lines[i] 
    values=line.split("     ")

    x_vals.append(float(values[0]))
    y_vals.append(float(values[1]))

plt.plot(x_vals, y_vals,'ro-')

And you could still use the data in a scatter plot if required.

share|improve this answer
    
Tnx, That's working exactly:) –  Negin Feb 20 at 15:25

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.