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up vote 0 down vote favorite

i have visited similar question here but not getting what i want in php. Suppose i have 2 arrays. All checking should be case insensitive. say Field0 is same as field0 or fiEld1 is same as Field1. 

array1 is array(
"0"=>"field0",
"1"=>"field1",
"2"=>"field2",
"3"=>"field3",
);

array2 is array(
"0"=>"field3",
"1"=>"field2",
"2"=>"field0",
"3"=>"field1",
"4"=>"field6",
"5"=>"field5",
);

Now I want array2 to be sorted based on array1 like the following: 

array2 is array(
"0"=>"field0",
"1"=>"field1",
"2"=>"field2",
"3"=>"field3",
"4"=>"field6",
"5"=>"field5",
);

look here array1 has 4 elements so array2 should be sorted based exactly 4 elements of array1 and rest 2 element (index 4,5 of array2) should as it is in array2 before.

share|improve this question

3 Answers 3

up vote 2 down vote accepted

Try array_intersect combined with array_diff:

<?php
$array1 = array(
    "0"=>"field0",
    "1"=>"field1",
    "2"=>"field2",
    "3"=>"field3",
);

$array2 = array(
    "0"=>"field3",
    "1"=>"field2",
    "2"=>"field0",
    "3"=>"field1",
    "4"=>"field6",
    "5"=>"field5",
);


$array3 = array_merge(
    array_intersect($array1, $array2), 
    array_diff($array2, $array1)
);

var_dump($array3);

Update

For a case insensitive approach, use array_map to guarantee all entries in both arrays are lower-cased:

$array3 = array_map('strtolower', $array1);
$array4 = array_map('strtolower', $array2);

$array5 = array_merge(
    array_intersect($array3, $array4), 
    array_diff($array4, $array3)
);

var_dump($array5);
share|improve this answer
    
if i change the case of the value of array1 or array2 then sort will be changed. could you make it case insensitive? –  Samiul Feb 3 '14 at 16:48
    
Do you also want to preserve the original case of the arrays? –  watcher Feb 3 '14 at 16:58
    
yes the case of array2 should be intact –  Samiul Feb 3 '14 at 17:01
    
See my update for a case-insensitive approach –  watcher Feb 3 '14 at 17:37
up vote 1 down vote

Assuming that array 2 is always bigger than array 1:

$array2 = array_merge($array1, array_diff($array2, $array1));
share|improve this answer
up vote -2 down vote

It's really easy :

$array = $array1 + $array2
share|improve this answer
    
This will not work, as this only computes the union between the two arrays. See php.net/manual/en/language.operators.array.php –  watcher Feb 3 '14 at 16:32
    
I tested it, it works. –  jgroenen Feb 3 '14 at 16:32
    
Sorry, but :$array1 = array( "0"=>"field0", "1"=>"field1", "2"=>"field2", "3"=>"field3", ); $array2 = array( "0"=>"field3", "1"=>"field2", "2"=>"field0", "3"=>"field1", "4"=>"field6", "5"=>"field5", ); var_dump($array1 + $array2); [code] array(6) { [0] => string(6) "field0" [1] => string(6) "field1" [2] => string(6) "field2" [3] => string(6) "field3" [4] => string(6) "field6" [5] => string(6) "field5" } [/code] –  hannibal-dss Feb 3 '14 at 16:33
    
It may work in this one case, but is relying on a lot of assumptions about the input data. perhaps the onus should be on the OP to provide a bit more insight, but in general this will not work. See the first example in the man page I linked to. –  watcher Feb 3 '14 at 16:36
    
I agree, works only for this exact input. –  jgroenen Feb 3 '14 at 16:37

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