The "syntax error unexpected ','" error is occurring here:
$foo1 = ($foo2, true);
Is the comma not suppose to be there?
2 Answers
You are either trying to create an array:
$foo1 = array($foo2, true);
Or calling a function:
$foo1 = myFunc($foo2, true);
Or trying to use a C comma expression, which PHP does not support (then again in that case $foo1 would just be assigned to true).
answered Dec 28, 2010 at 7:38
2 Comments
heximal
btw, array() is also function :)
BoltClock
@heximal: No, it's a language construct. The manual lists it as a function only because it does the same for
include, require, echo, print, etc, which are all language constructs. Syntactically you can call them like functions, but they're not.This is not a valid php expression.
$foo =myfunc($foo2, true);
Will call the function myfunc with the parameters $foo2 and true. The result will then be assigned to $foo.
$foo = array($foo2, true);
Will create a new array with two elements($foo2 and true)
$foo = ($foo2, true);
Will just throw a parse error because the only valid symbols between to variables in this context are operators(+,-,%,AND,...).
foo($foo2, true);, the function name being the difference. ;)